Introduction to General, Organic and Biochemistry
12th Edition
ISBN: 9780357119303
Author: Bettelheim, Frederick A., Brown, William H., Campbell, Mary K., FARRELL, Shawn O., Torres, Omar
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 3, Problem 49P
Interpretation Introduction
Interpretation:
The reason should be determined why hydrogen can’t have more than two electrons in its valence shell.
Concept Introduction:
The octet rule states that atoms of a variety of elements enter into chemical combination so as to reach the configuration of eight electrons in their outermost shell. They do so by either transference of electrons or by mutual sharing of electrons.
A covalent bond is formed by sharing of same number of electrons between two atoms to complete their octet. Atoms taking part in covalent bond formation may share one, two or three electron pairs thus forming single, double and triple bond respectively.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
I need help on my practice final, if you could explain how to solve this that would be extremely helpful for my final thursday. Please dumb it down chemistry is not my strong suit. If you could offer strategies as well to make my life easier that would be beneficial
None
None
Chapter 3 Solutions
Introduction to General, Organic and Biochemistry
Ch. 3.1 - Problem 3-1 Show how the following chemical...Ch. 3.3 - Problem 3-2 Judging from their relative positions...Ch. 3.4 - Problem 3-3 Write the formulas for the ionic...Ch. 3.5 - Problem 3-4 Name these binary ionic compounds: (a)...Ch. 3.5 - Prob. 3.5QCCh. 3.5 - Problem 3-6 Give each binary compound a systematic...Ch. 3.5 - Problem 3-7 Name these ionic compounds, each of...Ch. 3.6 - Prob. 3.8QCCh. 3.6 - Prob. 3.9QCCh. 3.6 - Prob. 3.10QC
Ch. 3.6 - Prob. 3.11QCCh. 3.7 - Prob. 3.12QCCh. 3.8 - Prob. 3.13QCCh. 3.8 - Prob. 3.14QCCh. 3.9 - Problem 3-15 Predict all bond angles for these...Ch. 3.10 - Problem 3-16 Which of these molecules are polar?...Ch. 3 - 3-17 Answer true or false. (a) The octet rule...Ch. 3 - 3-18 How many electrons must each atom gain or...Ch. 3 - 3-19 Show how each chemical change obeys the octet...Ch. 3 - 3-20 Show how each chemical change obeys the octet...Ch. 3 - 3-21 Write the formula for the most stable ion...Ch. 3 - 3-22 Why is Li- not a stable ion?Ch. 3 - 3-23 Predict which ions are stable: (a) (b) (c)...Ch. 3 - 3-24 Predict which ions are stable: (a) Br2- (b)...Ch. 3 - 3-25 Why are carbon and silicon reluctant to form...Ch. 3 - 3-26 Table 3-2 shows the following ions of copper:...Ch. 3 - 3-27 Answer true or false. (a) For Group lA and...Ch. 3 - 3-28 Name each polyatomic ion. (a) HCO3- (b) NO2-...Ch. 3 - 3-29 Answer true or false. (a) According to the...Ch. 3 - Prob. 14PCh. 3 - 3-31 Why does electronegativity generally increase...Ch. 3 - 3-32 Judging from their relative positions in the...Ch. 3 - Prob. 17PCh. 3 - 3-34 Which of these bonds is the most polar? The...Ch. 3 - 3-35 Classify each bond as nonpolar covalent,...Ch. 3 - 3-36 Classify each bond as nonpolar covalent,...Ch. 3 - 3-37 Answer true or false. (a) An ionic bond is...Ch. 3 - 3-38 Complete the chart by writing formulas for...Ch. 3 - 3-39 Write a formula for the ionic compound formed...Ch. 3 - Prob. 24PCh. 3 - 3-41 Describe the structure of sodium chloride in...Ch. 3 - 3-42 What is the charge on each ion in these...Ch. 3 - 3-43 Write the formula for the compound formed...Ch. 3 - 3-44 Write the formula for the ionic compound...Ch. 3 - 3-45 Which formulas are not correct? For each that...Ch. 3 - 3-46 Which formulas are not correct? For each that...Ch. 3 - 3-47 Answer true or false. (a) The name of a...Ch. 3 - 3-48 Potassium chloride and potassium bicarbonate...Ch. 3 - Prob. 33PCh. 3 - 3-50 Name the polyatomic ion(s) in each compound....Ch. 3 - 3-51 Write the formulas for the ions present in...Ch. 3 - Prob. 36PCh. 3 - 3-53 Write formulas for the following ionic...Ch. 3 - 3-54 Write formulas for the following ionic...Ch. 3 - Prob. 39PCh. 3 - 3-56 How many covalent bonds are normally formed...Ch. 3 - 3-57 What is: (a) A single bond? (b) A double...Ch. 3 - 3-58 In Section 2-3B, we saw that there are seven...Ch. 3 - Prob. 43PCh. 3 - Prob. 44PCh. 3 - Prob. 45PCh. 3 - Prob. 46PCh. 3 - 3-63 What is the difference between (a) a bromine...Ch. 3 - 3-64 Acetylene (C2H2), hydrogen cyanide (HCN), and...Ch. 3 - Prob. 49PCh. 3 - 3-66 Why can’t second-row elements have more than...Ch. 3 - 3-67 Why does nitrogen have three bonds and one...Ch. 3 - 3-68 Draw a Lewis structure of a covalent compound...Ch. 3 - Prob. 53PCh. 3 - 3-70 Draw a Lewis structure of a covalent compound...Ch. 3 - Prob. 55PCh. 3 - Prob. 56PCh. 3 - Prob. 57PCh. 3 - 3-74 Answer true or false. (a) A binary covalent...Ch. 3 - Prob. 59PCh. 3 - Prob. 60PCh. 3 - 3-77 Ozone, O3, is an unstable blue gas with a...Ch. 3 - 3-78 Nitrous oxide, N20, laughing gas, is a...Ch. 3 - 3-79 Answer true or false. (a) The letters VSEPR...Ch. 3 - Prob. 64PCh. 3 - Prob. 65PCh. 3 - 3-82 Hydrogen and nitrogen combine in different...Ch. 3 - Prob. 67PCh. 3 - Prob. 68PCh. 3 - Prob. 69PCh. 3 - Prob. 70PCh. 3 - 3-87 Consider the molecule boron trffluoride, BF3....Ch. 3 - Prob. 72PCh. 3 - 3-89 Is it possible for a molecule to have no...Ch. 3 - Prob. 74PCh. 3 - Prob. 75PCh. 3 - Prob. 76PCh. 3 - Prob. 77PCh. 3 - Prob. 78PCh. 3 - Prob. 79PCh. 3 - Prob. 80PCh. 3 - Prob. 81PCh. 3 - Prob. 82PCh. 3 - 3-99 Knowing what you do about covalent bonding in...Ch. 3 - Prob. 84PCh. 3 - Prob. 85PCh. 3 - Prob. 86PCh. 3 - Prob. 87PCh. 3 - Prob. 88PCh. 3 - 3-105 Consider the structure of Vitamin E shown...Ch. 3 - 3-106 Consider the structure of Penicillin G shown...Ch. 3 - 3-107 Ephedrine, a molecule at one time found in...Ch. 3 - Prob. 92PCh. 3 - 3-109 Until several years ago, the two...Ch. 3 - 3-110 Name and write the formula for the fluorine...Ch. 3 - Prob. 95PCh. 3 - Prob. 96PCh. 3 - Prob. 97PCh. 3 - Prob. 98PCh. 3 - Prob. 99PCh. 3 - Prob. 100PCh. 3 - Prob. 101PCh. 3 - Prob. 102PCh. 3 - 3-119 Perchloroethylene, which is a liquid at room...Ch. 3 - 3-120 Vinyl chloride is the starting material for...Ch. 3 - 3-121 Tetrafluoroethylene is the starting material...Ch. 3 - 3-122 Some of the following structural formulas...Ch. 3 - 3-123 Sodium borohydride, NaBH4, has found wide...Ch. 3 - Prob. 108PCh. 3 - Prob. 109PCh. 3 - Prob. 110PCh. 3 - Prob. 111PCh. 3 - Prob. 112PCh. 3 - Consider the structure of Fluoxetine (or Prozac)...Ch. 3 - Consider the structure of lipoic acid shown below,...Ch. 3 - Prob. 115P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Nonearrow_forwardComment on the following paragraph. In halides, MXn stoichiometry does not require a value of n so large as to prevent the approach of M+ ions, for steric or electrostatic reasons.arrow_forwardExplain Wade's rules, Indicate what the letters S and n represent in the formula.arrow_forward
- Which of the terms explain the relationship between the two compounds? CH2OH Он Он Он Он α-D-galactose anomers enantiomers diastereomers epimers CH2OH ОН O он Он ОН B-D-galactosearrow_forwardHi, I need help on my practice final, If you could offer strategies and dumb it down for me with an explanation on how to solve that would be amazing and beneficial.arrow_forwardHi I need help with my practice final, it would be really helpful to offer strategies on how to solve it, dumb it down, and a detailed explanation on how to approach future similar problems like this. The devil is in the details and this would be extremely helpfularrow_forward
- In alpha-NbI4, Nb4+ should have the d1 configuration (bond with paired electrons: paramagnetic). Please comment.arrow_forwardHi, I need help on my practice final, if you could explain how to solve it offer strategies and dumb it down that would be amazing. Detail helpsarrow_forwardBriefly explain the following paragraph: both the distortion of symmetry and the fact that the solid is diamagnetic indicate the existence of a Nb-Nb bond.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
- Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage LearningGeneral, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
General, Organic, and Biological Chemistry
Chemistry
ISBN:9781285853918
Author:H. Stephen Stoker
Publisher:Cengage Learning
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Stoichiometry - Chemistry for Massive Creatures: Crash Course Chemistry #6; Author: Crash Course;https://www.youtube.com/watch?v=UL1jmJaUkaQ;License: Standard YouTube License, CC-BY
Bonding (Ionic, Covalent & Metallic) - GCSE Chemistry; Author: Science Shorts;https://www.youtube.com/watch?v=p9MA6Od-zBA;License: Standard YouTube License, CC-BY
General Chemistry 1A. Lecture 12. Two Theories of Bonding.; Author: UCI Open;https://www.youtube.com/watch?v=dLTlL9Z1bh0;License: CC-BY