Explanation Given data: Refer to Figure 3.93 in the textbook for mesh analysis. Calculation: Modified given figure with the assumed current directions is shown in Figure 1 From Figure 1, write the current relation. i 2 = i + i 3 i = i 2 − i 3 (1) Apply Kirchhoff’s voltage law to loop 1 with current i 1 in Figure 1. ( 4 kΩ ) ( i 1 − i 4 ) + ( 1 kΩ ) ( i 1 − i 2 ) + 4 − 6 = 0 4000 i 1 − 4000 i 4 + 1000 i 1 − 1000 i 2 = 2 { ∵ 1 kΩ = 1000 Ω } 5000 i 1 − 1000 i 2 − 4000 i 4 = 2 5 i 1 − i 2 − 4 i 4 = 0.002 (2) Apply Kirchhoff’s voltage law to loop 2 with current i 2 in Figure 1. ( 2 kΩ ) ( i 2 − i 4 ) + ( 10 kΩ ) ( i 2 − i 3 ) − 4 + ( 1 kΩ ) ( i 2 − i 1 ) = 0 2000 i 2 − 2000 i 4 + 10000 i 2 − 10000 i 3 + 1000 i 2 − 1000 i 1 = 4 − 1000 i 1 + 13000 i 2 − 10000 i 3 − 2000 i 4 = 4 − i 1 + 13 i 2 − 10 i 3 − 2 i 4 = 0.004 (3) Apply Kirchhoff’s voltage law to loop 3 with current i 3 in Figure 1. ( 5 kΩ ) ( i 3 − i 4 ) − 3 + ( 10 kΩ ) ( i 3 − i 2 ) = 0 5000 i 3 − 5000 i 4 + 10000 i 3 − 10000 i 2 = 3 − 10000 i 2 + 15000 i 3 − 5000 i 4 = 3 − 10 i 2 + 15 i 3 − 5 i 4 = 0

6th Edition

ISBN: 9780078028229

Author: Charles K Alexander, Matthew Sadiku

Publisher: McGraw-Hill Education

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Voltage Division Method

In the electronics branch, a voltage divider is required to produce a section of its input voltage as an output. This basic circuit may be prepared with two resistors or any passive elements along with the voltage source. The circuit resistors are attach…

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Chapter 3, Problem 48P

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Find the current through the 10 kΩ resistor in the circuit of Figure 3.93 using MATLAB.

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Chapter 3, Problem 47P

Chapter 3, Problem 49P

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