Explanation Given data: Refer to Figure 3.90 in the textbook for mesh analysis. Calculation: Modified given figure with the assumed current directions is shown in Figure 1 From Figure 1, write the current relations. i 1 − i 2 = 4 A (1) i o = i 3 − i 2 (2) Modified given figure for the supermesh analysis is shown in Figure 2. Apply supermesh analysis in Figure 2. 100 i 2 + 50 ( i 2 − i 3 ) + 50 ( i 1 − i 3 ) = 400 100 i 2 + 50 i 2 − 50 i 3 + 50 i 1 − 50 i 3 = 400 50 i 1 + 150 i 2 − 100 i 3 = 400 0.5 i 1 + 1.5 i 2 − i 3 = 4 (3) Apply Kirchhoff’s voltage law to loop 3 with current i 3 in Figure 1. 50 ( i 3 − i 1 ) + 50 ( i 3 − i 2 ) + 100 i 3 = 50 50 i 3 − 50 i 1 + 50 i 3 − 50 i 2 + 100 i 3 = 50 − 50 i 1 − 50 i 2 + 200 i 3 = 50 − 0.5 i 1 − 0.5 i 2 + 2 i 3 = 0.5 (4) Rearrange equation (1). i 1 = 4 + i 2 (5) Substitute equation (5) in (3). 0.5 ( 4 + i 2 ) + 1.5 i 2 − i 3 = 4 2 + 0.5 i 2 + 1.5 i 2 − i 3 = 4 2 i 2 − i 3 = 4 − 2 2 i 2 − i 3 = 2 (6) Substitute equation (5) in (4)

6th Edition

ISBN: 9780078028229

Author: Charles K Alexander, Matthew Sadiku

Publisher: McGraw-Hill Education

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Voltage Division Method

In the electronics branch, a voltage divider is required to produce a section of its input voltage as an output. This basic circuit may be prepared with two resistors or any passive elements along with the voltage source. The circuit resistors are attach…

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Chapter 3, Problem 44P

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Find the current io in the circuit of Figure 3.84.

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Chapter 3, Problem 43P

Chapter 3, Problem 45P

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Find the current i o in the circuit of Figure 3.84.

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Find the current io in the circuit of Figure 3.84.

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Chapter 3 Solutions