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Organic Chemistry
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- The acid dissociation constant for a weak acid HX at 25°C is 1.9 x10-6. Calculate the free energy of formation for X–(aq) at 25°C. The standard free energies of HX(aq) and H+(aq) at 25°C are –245.4 kJ/mol and 0, respectively.arrow_forwardSome H2PO4- and HPO42- are added to water such that the concentration of each is the same value, 5.25 mmol L-1 (pKa = 2.1, 6.8, 12.4). The water was initially at pH 6.55 and 25.0 °C. Calculate ΔGrxn in kJ mol-1. (R = 8.3145 J mol-1 K-1)arrow_forward5. One of the key steps in the tricarboxylic acid (TCA) cycle is the hydration of fumarate to malate: Fumarate-² + H₂O = Malate-2 The standard reaction Gibbs free energy and enthalpy for this reactions are -880 cal/mol and 3560 cal/mol, respectively. (a) What is the equilibrium constant for this reaction (25 °C)? (b) Is the reaction favorable (spontaneous) at 25 °C? (c) What is the equilibrium constant of this reaction under physiological conditions (37 °C)? (d) Is this reaction favorable at 37 °C?arrow_forward
- Ka = 4.5 × 10-4 at 25°C of nitrous acid (HNO2). What is the ΔG value at equilibrium?arrow_forwardGiven the following data: 2C6H6 (l) + 15O2 (g) → 12CO2 (g) + 6 H2O (l) ΔG° = –6399 kJ C (s) + O2 (g) → CO2 (g) ΔG° = –394 kJ H2 (g) + ½ O2 (g) → H2O(l) ΔG° = –273 kJ Calculate ΔG° for the reaction 6 C(s) + 3 H2(g) ----> C6H6(l) ΔG° = ???arrow_forwardWhy is ΔTmetal < 0? Why is ΔTwaterarrow_forward
- The pKb of the organic base nicotine (denoted Nic) is 5.98. Write the corresponding protonation reaction, the deprotonation reaction of the conjugate acid, and the value of pKa for nicotine.arrow_forwardA student determines the value of the equilibrium constant to be 8.18x10-37 for the following reaction. H₂S(g) + 2H₂O(l)—3H₂(g) + SO₂(g) Based on this value of Keq: AG° for this reaction is expected to be (greater, less) zero. than Calculate the free energy change for the reaction of 1.68 moles of H₂S(g) at standard conditions at 298K. AG rxn= kJarrow_forwardThe following equilibrium constants have been determined for hydrosulfuric acid at 25ºC: H2S(aq) ⇌ H+(aq) + HS–(aq) K′c = 9.5 × 10–8 HS–(aq) ⇌ H+(aq) + S2–(aq) K″c = 1.0 × 10–19 Calculate the equilibrium constant for the following reaction at the same temperature. H2S(aq) ⇌ 2H+(aq) + S2–(aq)arrow_forward
- Calculate the value of Δ?∘rxnΔGrxn∘ for the following reaction at 278 K. Ka = 2.9 × 10–8 and assume Ka does not change significantly with temperature. HClO(aq) + H2O(l) <--> ClO-(aq) + H3O+(aq)arrow_forwardA student determines the value of the equilibrium constant to be 3.67×10-18 for the following reaction. Fe3O4(s) + 4H₂(g) →→→3Fe(s) + 4H₂O(g) Based on this value of Keq: AGO for this reaction is expected to be (greater, less) than zero. Calculate the free energy change for the reaction of 1.67 moles of Fe3O4(s) at standard conditions at 298K. AGᵒrxn KJarrow_forwardCoral structures found in the Great Barrier Reef are composed of calcium carbonate, CaCO3, and are under threat of dissolution due to ocean acidification. Consider the following equilibrium reaction equation. CaCO3(s) + CO2(aq) + H2O(l) ⇌ Ca2+(aq) + 2HCO3–(aq) Write the expression for the equilibrium constant, Kc for this reaction. Predict whether the pH of the ocean will increase or decrease as a result of a decrease in the partial pressure of carbon dioxide in the atmosphere (circle your answer). Calculate the molar solubility (s) of calcium carbonate in water at 25 °C when Ksp = 4.5 ´ 10–9.arrow_forward
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