The carbon–oxygen bond lengths and the equal negative charge on oxygens of an acetate ion are to be explained by drawing resonance structures. Concept introduction: Resonance is the phenomenon of describing delocalized electrons in certain molecular ions through various forms or resonance structures and the forms contributing to the hybrid form. The positions of electrons are different, without effecting the positions of the nuclei. The effect of delocalization is caused by resonance, where the negative charge is distributed among the oxygen atoms in a carboxylate ion. The rules for drawing resonance structures are as follows: Only nonbonding electron pairs and pi electrons can participate in conjugation in the formation of various resonating structures. The single bonds present in the molecule do not break or form in the resonance structures. The placement of atoms present in the molecule remains fixed. The octet of all atoms is completely filled.

Question

Want to see the full answer?

Answer 1

Question

Chapter 3, Problem 13PP

Interpretation Introduction

Interpretation:

The carbon–oxygen bond lengths and the equal negative charge on oxygens of an acetate ion are to be explained by drawing resonance structures.

Concept introduction:

Resonance is the phenomenon of describing delocalized electrons in certain molecular ions through various forms or resonance structures and the forms contributing to the hybrid form.

The positions of electrons are different, without effecting the positions of the nuclei.

The effect of delocalization is caused by resonance, where the negative charge is distributed among the oxygen atoms in a carboxylate ion.

The rules for drawing resonance structures are as follows:

Only nonbonding electron pairs and pi electrons can participate in conjugation in the formation of various resonating structures.

The single bonds present in the molecule do not break or form in the resonance structures.

The placement of atoms present in the molecule remains fixed.

The octet of all atoms is completely filled.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

A sample of hydrated magnesium sulfate (MgSO4⋅xH2O) is analyzed using thermogravimetric analysis (TGA). The sample weighs 2.50 g initially and is heated in a controlled atmosphere. As the temperature increases, the water of hydration is released in two stages: (a) The first mass loss of 0.72 g occurs at 150°C, corresponding to the loss of a certain number of water molecules. (b) The second mass loss of 0.90 g occurs at 250°C, corresponding to the loss of the remaining water molecules. The residue is identified as anhydrous magnesium sulfate (MgSO4) Questions: (i) Determine the value of x (the total number of water molecules in MgSO4⋅xH2O) (ii) Calculate the percentage of water in the original sample. Write down the applications of TGA.

The solubility product of iron(III) hydroxide (Fe(OH)3) is 6.3×10−38. If 50 mL of a 0.001 M FeCl3 solution is mixed with 50 mL of a 0.005 M NaOH solution, will Fe(OH)3 precipitate? Show all step-by-step calculations. To evaluate the equilibrium constant, we must express concentrations of solutes in mol/L, gases in bars, and omit solids, liquids, and solvents. Explain why.

Predict the major products of this organic reaction.