Custom eBook for Organic Chemistry
Custom eBook for Organic Chemistry
2nd Edition
ISBN: 9798214171104
Author: Straumanis
Publisher: Cengage Custom
bartleby

Concept explainers

Question
Book Icon
Chapter 3, Problem 3E

(a)

Interpretation Introduction

Interpretation: The reason behind equal potential energies for all four sp3 -hybrid orbitals should be explained.

Concept introduction: Two or more of orbitals undergo redistributions of their different energies so as to form mathematically averaged orbitals in terms of energy although they may differ in shape and orientation. This phenomenon is referred as hybridization.

(b)

Interpretation Introduction

Interpretation: The reason behind energy level line for sp3 hybrid orbital placed three-quarters between the line for 2s and 2p should to be explained.

Concept introduction: Two or more of orbitals undergo redistributions of their different energies so as to form mathematically averaged orbitals in terms of energy although they may differ in shape and orientation. This phenomenon is referred as hybridization. The new hybrid orbitals are always equal in number to number of atomic orbitals that combine.

(c)

Interpretation Introduction

Interpretation: The diagram given below for sp3 hybrid nitrogen should be completed.

  Custom eBook for Organic Chemistry, Chapter 3, Problem 3E , additional homework tip  1

Concept introduction: Two or more of orbitals undergo redistributions of their different energies so as to form mathematically averaged orbitals in terms of energy although they may differ in shape and orientation.

The energy and orientation of the new hybrid orbital depends upon by the kind and number of orbitals used in the hybridization. For instance, when one 2s and three 2p orbital combines to form four sp3 hybrid orbital energy are redistributed so that each orbital gets equivalent share and they become degenerate.

(d)

Interpretation Introduction

Interpretation: The second-row element shown in left diagram of below image and hybridization state in right diagram of below image should be identified.

  Custom eBook for Organic Chemistry, Chapter 3, Problem 3E , additional homework tip  2

Concept introduction: Hund’s rule of maximum multiplicity states that electrons are not allowed to be paired up until each degenerate set of orbital has got at least one electron.

(d)

Interpretation Introduction

Interpretation: Whether the unpaired electrons in below figure are in accordance with Hund’s rule or not should be identified.

  Custom eBook for Organic Chemistry, Chapter 3, Problem 3E , additional homework tip  3

Concept introduction: Hund’s rule of maximum multiplicity states that electrons are not allowed to be paired up until each degenerate set of orbital has got at least one electron.

Blurred answer
Students have asked these similar questions
Can you please help mne with this problem. Im a visual person, so can you redraw it, potentislly color code and then as well explain it. I know im given CO2 use that to explain to me, as well as maybe give me a second example just to clarify even more with drawings (visuals) and explanations.
Part 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff: Ag₂ CO3 = 2 Ag+ caq) + co} (aq) ksp = 8.10 × 10-12 Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5 a) which salt will precipitate first? (b) What % of the first anion precipitated will remain in the solution. by the time the second anion starts to precipitate? (c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate explanation per answer
Part 4. Butanoic acid (ka= 1.52× 10-5) has a partition coefficient of 3.0 (favors benzene) when distributed bet. water and benzene. What is the formal concentration of butanoic acid in each phase when 0.10M aqueous butanoic acid is extracted w❘ 25 mL of benzene 100 mL of a) at pit 5.00 b) at pH 9.00
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Organic Chemistry: A Guided Inquiry
Chemistry
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Cengage Learning
Text book image
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Text book image
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning