The reason should be determined why hydrogen can’t have more than two electrons in its valence shell. Concept Introduction: The octet rule states that atoms of a variety of elements enter into chemical combination so as to reach the configuration of eight electrons in their outermost shell. They do so by either transference of electrons or by mutual sharing of electrons. A covalent bond is formed by sharing of same number of electrons between two atoms to complete their octet. Atoms taking part in covalent bond formation may share one, two or three electron pairs thus forming single, double and triple bond respectively.
The reason should be determined why hydrogen can’t have more than two electrons in its valence shell. Concept Introduction: The octet rule states that atoms of a variety of elements enter into chemical combination so as to reach the configuration of eight electrons in their outermost shell. They do so by either transference of electrons or by mutual sharing of electrons. A covalent bond is formed by sharing of same number of electrons between two atoms to complete their octet. Atoms taking part in covalent bond formation may share one, two or three electron pairs thus forming single, double and triple bond respectively.
Solution Summary: The author explains the octet rule, which states that atoms of a variety of elements enter into chemical combination so as to reach the configuration of eight electrons in their outermost shell.
The reason should be determined why hydrogen can’t have more than two electrons in its valence shell.
Concept Introduction:
The octet rule states that atoms of a variety of elements enter into chemical combination so as to reach the configuration of eight electrons in their outermost shell. They do so by either transference of electrons or by mutual sharing of electrons.
A covalent bond is formed by sharing of same number of electrons between two atoms to complete their octet. Atoms taking part in covalent bond formation may share one, two or three electron pairs thus forming single, double and triple bond respectively.
Draw the virtual orbitals for the planar and pyramidal forms of CH3 and for the linear and bent forms of CH2
Q2: Draw the molecules based on the provided nomenclatures below:
(2R,3S)-2-chloro-3-methylpentane:
(2S, 2R)-2-hydroxyl-3,6-dimethylheptane:
Q3: Describes the relationship (identical, constitutional isomers, enantiomers or diastereomers)
of each pair of compounds below.
ག
H
CH3
OH
OH
CH3
H3C
OH
OH
OH
//////////
C
CH3
CH3
CH3
CH3
H3C
CH 3
C/III.....
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COOH
H
нош.....
H
2
OH
HO
CH3
HOOC
H
CH3
CH3
CH3
Br.
H
H
Br
and
H
H
H
H
Chapter 3 Solutions
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