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If the resistance between the outside terminals of a linear potentiometer is

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Introductory Circuit Analysis; Laboratory Manual For Introductory Circuit Analysis Format: Kit/package/shrinkwrap
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- Find the operating point and the load line of a voltage-divider JFET biasing circuit using the following parameters: VGS(0) = -1.3 and Vcc = 15 volts. Assume ipss = 20 mA, RG₁ = RG2 = 10 kn, RD = 300, and Rs = 1 kn. Use Fig. 4b for the IV characteristic of the JFET. 20nA GS=-1.3 GS 10nA- 50 100 150 200 ID(J1) UDS Fig. 4b. The IV characteristics of an n-channel JFET (J113). The plots are for VGs increments of 0.05 volts. VGS(0) -1.3. The yellow and blue load lines are for examples 2 &3, respectively.arrow_forwardDesign the JFET circuit for the largest in swing. Use the self-bias circuit shown in Fig. 6. Assume that VGS (0) = -1.3 and Vcc = 15 volts. Furthermore, assume that ipss = 20 mA. Using Fig. 4b, draw the load line and identify the Q point. Explain why this will allow the largest swing. Use ip = ipss (1- VGS VGS(0) to show what happens to i, and vps when you have a swing of 0.2 volts in vcs form its operating point (that is, change vas by ±0.2 volts and compute the corresponding iD and VDs). RD RG Rs 0 20nA GS=-1.3 VGS 12 10nA -0- Fig. 6. Circuit for Examples 2 &3. BA-C 50 100 150 200 □ ID(J1) UDS Fig. 4b. The IV characteristics of an n-channel JFET (J113). The plots are for VGs increments of 0.05 volts. VGS(0) -1.3. The yellow and blue load lines are for examples 2 &3, respectively.arrow_forwardplease do the correct VI chrastaristics curve on excel. I am not sure if mine is correctarrow_forward
- please do the correct VI chrastaristics curve on excel. I am not sure if mine is correct. Note the two curves in the picture are for both but its two tries and i dont know which is correct, and probebly both are wrong SCR (Forward Bias Condition) NO VAA VG= 0V, IG=0 mA VG= 5V, IG=4.07mA VG= 10V, IG=9.05mA VAK (V) IAK(mA) VAK (V) IAK(mA) VAK (V) IAK(mA) 1 0 0 0 0 0 0 0 2 5 0.576 4.42 mA 0.576 4.42 mA 0.576 4.43 3 10 7.99 2 0.598 9.4 0.598 9.4 4 15 14.99 0.003 0.612 14.4 0.612 14.4 5 20 19.994 0.004 0.622 19.4 0.622 19.4 6 25 0.63 24.4 0.63 24.4 0.63 24.4 4 30 0.637 29.4 0.637 29.4 0.637 29.4 8 40 0.65 39.4 0.65 39.4 0.65 39.4 9 50 0.66 49.3 0.66 49.3 0.66 49.3 10 60 0.67 59.3 0.67 59.3 0.67 59.3 11 70 0.679 69.3 0.679 69.3 SCR (Reversed Bias…arrow_forwardSee both images attachedarrow_forwardSee both images to understandarrow_forward
- Please see both images to answerarrow_forwardfeedback and open-loop gains. R2 RI =B=S Vi name the circuit, derive and find the oscillation RA Ca Rx 000arrow_forward5 Find the value of voltage Vy using nodal analysis (write and then solve the set of equations to get voltage Vx from your variables.) 43 LX + Vx да ww 1 23 дъх 83 38 wwarrow_forward
- help on this question about block diagram reduction?arrow_forward4) Find the valve of current if using nodal analys.3. (write and then solve the set of equations toget current Ex from your voltage variables.) M 3 ча + GA हुप 8Aarrow_forward2) Write but do not solve the set of Nodal equations for this circuit. 35 34 M x www 2 3A ↑ -+ 1v {7 ww 6 Bixarrow_forward
- Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning
