Chapter 3, Problem 2SEPP

Interpretation Introduction

Interpretation:

The mass of ${\text{Ca(H}}_2{\text{PO}}_4{\text{)}}_2$ produced, when the entire limiting reagent has converted into the product, is to be calculated.

Concept introduction:

Limiting reagent is the reagent that limits the amount of product during the reaction. Actually, it determines the product, as it is present in a lesser amount than required. Other reagents will remain present in excess.

Excess reactant is the reactant which is present in larger amount than required.

The required amount of ${\text{Ca(H}}_2{\text{PO}}_4{\text{)}}_2$ can be calculated by:

$\text{Mass}\text{of}{\text{Ca(H}}_2{\text{PO}}_4{\text{)}}_2=\frac{\text{number of moles }\times \text{molar mass}\text{of}{\text{Ca(H}}_2{\text{PO}}_4{\text{)}}_2}{\text{number of moles }\times \text{molar mass}\text{of}{\text{Ca}}_{\text{5}}{{\text{(PO}}_{\text{4}}\text{)}}_{\text{3}}\text{F}}\text{×}\text{mass}\text{of}{\text{Ca}}_{\text{5}}{{\text{(PO}}_{\text{4}}\text{)}}_{\text{3}}\text{F}$