Chapter 3, Problem 3SEPP

Interpretation Introduction

Interpretation:

The mass of excess reactant left in the given reaction is to be calculated.

Concept introduction:

Limiting reagent is the reagent that limits the amount of product during the reaction. Actually, it determines the product, as it is present in a lesser amount than required. Other reagents will remain present in excess.

Excess reagent is the reagent that is present in excess, that is, more than required.

The molar mass can be calculated by

$\text{molar}\text{mass}\text{=}\text{number}\text{of}\text{element×}\text{atomic}\text{mass}\text{of}\text{element}$

Example- $\begin{array}{l}{\text{Molar mass of H}}_{\text{2}}\text{O}\text{=}\text{number}\text{of}\text{atoms}\text{of}\text{H}\text{×}\text{atomic}\text{mass}\text{of}\text{H}\\ \text{+number}\text{of}\text{atoms}\text{of}\text{O}\text{×}\text{atomic}\text{mass}\text{of}\text{O}\end{array}$