Explanation Given info: The potential difference is 25.0 kV . Write the expression to calculate the work potential energy of electron. E = e V Here, E is the work potential energy of electron. e is the charge on electron. V is the potential difference. Substitute 1.6 × 10 − 19 C for e and 25.0 kV for V in above expression. E = 1.6 × 10 − 19 C × 25 kV × 1000 V 1 kV = 4 × 10 − 15 J Thus, the potential energy of electron is 4 × 10 − 15 J . Write the expression to calculate the Kinetic Energy of Electron with the help of classical approach. 1 2 m v 2 = E v = 2 E m Here, m is the mass of electron. v is the final speed of electron measured classically. E is the work potential energy of electron. Substitute 9.1 × 10 − 31 kg for m and 4 × 10 − 15 J for E in above expression. v = 2 × 4 × 10 − 15 J 9.1 × 10 − 31 kg = 0.978 × 10 8 m / s × 1c 3 × 10 8 m / s = 0

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Chapter 29, Problem 88PP

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Whether the speed of the electron when relativistic effects are included will be greater than, or less than or the same as compared to classical approach.

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Chapter 29, Problem 87PP

Chapter 29, Problem 89PP

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Whether the speed of the electron when relativistic effects are included will be greater than, or less than or the same as compared to classical approach.

Solution Summary: The author explains that the speed of the electron when relativistic effects are included will be greater than, or less than or the same as compared to classical approach.

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Whether the speed of the electron when relativistic effects are included will be greater than, or less than or the same as compared to classical approach.

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