Explanation Given info: The accelerated voltage is 25.0 kV . Write the expression to calculate the accelerating voltage when it is increased by a factor of 10 . V ′ = 10 V Here, V ′ is the accelerating voltage when it is increased by a factor of 10 . V is the accelerated voltage. Substitute 25.0 kV for V in above expression. V ′ = 10 × 25.0 keV = 250 keV Write the expression to calculate the work potential energy of electron. E = e V ′ Here, E is the work potential energy of electron. e is the charge on electron. V ′ is the accelerating voltage when it is increased by a factor of 10 . Substitute 1.6 × 10 − 19 C for e and 250 kV for V ′ in above expression. E = 1.6 × 10 − 19 C × 250 kV × 1000 V 1 kV = 4 × 10 − 14 J Thus, the potential energy of electron is 4 × 10 − 14 J . Write the expression to calculate the Kinetic Energy of Electron with the help of relativistic approach. ( 1 1 − v ′ 2 c 2 − 1 ) m c 2 = E v ′ = c 1 − ( E m c 2 + 1 ) − 2 Substitute 9

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Chapter 29, Problem 90PP

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The speed of an electron considering the relativistic approach when the accelerated voltage is increased by a factor of 10 .

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Chapter 29, Problem 89PP

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The speed of an electron considering the relativistic approach when the accelerated voltage is increased by a factor of 10 .

Solution Summary: The author explains how to determine the speed of an electron when the accelerated voltage is increased by a factor of 10.

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The speed of an electron considering the relativistic approach when the accelerated voltage is increased by a factor of 10 .

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