
(a)
Interpretation: Bonding and anti-bonding molecular orbitals has to be determined for the molecular orbitals of
Concept introduction:
Molecular orbital theory suggests that atomic orbitals of different atoms combines to create molecular orbitals.
Molecular orbitals can be constructed from linear combination of atomic orbitals.
Bonding orbotals are formed by the additive combination of atomic orbitals and the antibonding orbitals are formed by the substractive combination of atomic orbitals.
Antibonding orbital is a molecular orbital that results when two parallel atomic orbitals with opposite phases interact.
Antibonding orbitals have higher energy than the bonding molecular orbitals.
HOMO is a molecular orbital which is the abbrevation of Highest Occupied Molecular Orbital.
LUMO is also a molecular orbital which is the short form of Lowest Unoccupied Molecular Orbital.
If the lobes at the ends of the MO are in phase, then the MO is symmetric.
If the two lobes are out phase then the MO is antisymmetric.
(b)
Interpretation: HOMO and LUMO molecular orbitals in the ground state has to be determined for the molecular orbitals of
Concept introduction:
Molecular orbital theory suggests that atomic orbitals of different atoms combines to create molecular orbitals.
Molecular orbitals can be constructed from linear combination of atomic orbitals.
Bonding orbotals are formed by the additive combination of atomic orbitals and the antibonding orbitals are formed by the substractive combination of atomic orbitals.
Antibonding orbital is a molecular orbital that results when two parallel atomic orbitals with opposite phases interact.
Antibonding orbitals have higher energy than the bonding molecular orbitals.
Ground state and and exited states are the positions with lower and higher energy respectively.
HOMO is a molecular orbital which is the abbrevation of Highest Occupied Molecular Orbital.
LUMO is also a molecular orbital which is the short form of Lowest Unoccupied Molecular Orbital.
If the lobes at the ends of the MO are in phase, then the MO is symmetric.
If the two lobes are out phase then the MO is antisymmetric.
(c)
Interpretation: HOMO and LUMO molecular orbitals in the existed state has to be determined for the molecular orbitals of
Concept introduction:
Molecular orbital theory suggests that atomic orbitals of different atoms combines to create molecular orbitals.
Molecular orbitals can be constructed from linear combination of atomic orbitals.
Bonding orbotals are formed by the additive combination of atomic orbitals and the antibonding orbitals are formed by the substractive combination of atomic orbitals.
Antibonding orbital is a molecular orbital that results when two parallel atomic orbitals with opposite phases interact.
Antibonding orbitals have higher energy than the bonding molecular orbitals.
Ground state and and exited states are the positions with lower and higher energy respectively.
HOMO is a molecular orbital which is the abbrevation of Highest Occupied Molecular Orbital.
LUMO is also a molecular orbital which is the short form of Lowest Unoccupied Molecular Orbital.
If the lobes at the ends of the MO are in phase, then the MO is symmetric.
If the two lobes are out phase then the MO is antisymmetric.
(d)
Interpretation: Symmetric and anti-symmetric MOs has to be determined for the molecular orbitals of
Concept introduction:
Molecular orbital theory suggests that atomic orbitals of different atoms combines to create molecular orbitals.
Molecular orbitals can be constructed from linear combination of atomic orbitals.
Bonding orbotals are formed by the additive combination of atomic orbitals and the antibonding orbitals are formed by the substractive combination of atomic orbitals.
Antibonding orbital is a molecular orbital that results when two parallel atomic orbitals with opposite phases interact.
Antibonding orbitals have higher energy than the bonding molecular orbitals.
Ground state and and exited states are the positions with lower and higher energy respectively.
HOMO is a molecular orbital which is the abbrevation of Highest Occupied Molecular Orbital.
LUMO is also a molecular orbital which is the short form of Lowest Unoccupied Molecular Orbital.
If the lobes at the ends of the MO are in phase, then the MO is symmetric.
If the two lobes are out phase then the MO is antisymmetric.
(e)
Interpretation: The relationship between HOMO and LUMO and symmetric and antisymmetric molecular orbitals has to be determined.
Concept introduction:
Molecular orbital theory suggests that atomic orbitals of different atoms combines to create molecular orbitals.
Molecular orbitals can be constructed from linear combination of atomic orbitals.
Bonding orbotals are formed by the additive combination of atomic orbitals and the antibonding orbitals are formed by the substractive combination of atomic orbitals.
Antibonding orbital is a molecular orbital that results when two parallel atomic orbitals with opposite phases interact.
Antibonding orbitals have higher energy than the bonding molecular orbitals.
Ground state and and exited states are the positions with lower and higher energy respectively.
HOMO is a molecular orbital which is the abbrevation of Highest Occupied Molecular Orbital.
LUMO is also a molecular orbital which is the short form of Lowest Unoccupied Molecular Orbital.
If the lobes at the ends of the MO are in phase, then the MO is symmetric.
If the two lobes are out phase then the MO is antisymmetric.

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Chapter 28 Solutions
Organic Chemistry (8th Edition)
- Give the IUPAC name for this compound Hydrocarbon Condensed Formulas Hint C2H5 CH2CH3 expand that in all the formula Part A: (CH3)2CHCH(C2H5)CH2CH2CH3 Give the IUPAC name for this compound. Part B: CH2=C(C2H5)CH2CH2CH3 Give the IUPAC name for this compound. Part C: (CH3)2C=CHC(C2H5)=CH2 Give the IUPAC name for this compound. Part D: CH3C=CCH(C2H5)2 Give the IUPAC name for this compound. Part E: (CH3)3CC=CCH2CH=C(CH3)2arrow_forwardSelect/ Match the correct letter from the image below for the IUPAC names given below: A B C D 3 E F G H K L Part 1. 4-methylheptane For example.mmmm Answer Letter H _for part 1 Part 2. 2,4-dimethylhexane Part 3. 2,3-dimethylpentane Part 4. 2,2-dimethylhexane Part 5. 2-ethyl-1,1,3,3-tetramethylcyclopentane Part 6. 3-ethyl-2-methylpentanearrow_forwardCan u show the process as to how to get these?arrow_forward
- Sketch the expected 'H NMR spectra for the following compound. Label all of the H's in the structure and the corresponding signal for the spectra you sketch. Make sure you include the integration value and the splitting pattern for each signal Indicate how many signals you would expect in the 13C NMRarrow_forwardUse IUPAC naming rules to name the following hydrocarbon compounds: CH2-CH3 | a) CH-CH-CH2-CH-CH-CH3 b) | CH2 CH3 | CH3 CH3 \ / C=C H 1 H CH2-CH3 c) d) CH=C-CH3 e) CH3-CH2-CH2-CH=CH-CH3 f) CH2=CH-CH2-CH=CH-CH3 g) CH3-CH2-C = C-CH2-CH3 h)arrow_forwardQ5 Name the following : a. b. C. d. e.arrow_forward
- 25. Predict the major product of the following reaction. 1 equivalent of each of the starting materials was used. H₂C CH3 CH3 H3C H3C H3C. CH2 + H3C. heat CH3 CH H.C. CH3 H.C H.C CH3 CH CH3 CH3 A B C Earrow_forwardFind chemical structures based on the below information. a) Chemical formula C6H8O Compound is aromatic plus has two 1H NMR peaks that integrated for 3 each that are singlets (it could have more peaks in the 1H NMR b) Chemical Formula: C6H100 Compounds is conjugated 'H NMR has a signal that integrates for 6 and is a doublet IR spectra has a signal at 1730 cm-1arrow_forwardJaslev Propose a synthesis of the following starting from benzene and any other reagents and chemicals. No mechanisms are required. Indicate the condition for each step plus the major product for each step. More than two steps are required. Step 1 Step 2 مہد Brarrow_forward
- Part C: The line formula for another branched alkane is shown below. i. In the IUPAC system what is the root or base name of this compound? ii. How many alkyl substituents are attached to the longest chain? iii. Give the IUPAC name for this compound.arrow_forwardPart D: Draw the Structural Formula for 4-ethyl-2-methylhexane Part E. Draw the Structural Formula for 1-chloro-3,3-diethylpentane (Chloro = Cl)arrow_forwardPart B: The line formula for a branched alkane is shown below. a. What is the molecular formula of this compound? Number of C. Number of H b. How many carbon atoms are in the longest chain? c. How many alkyl substituents are attached to this chain?arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning

