Explanation 1) Concept: We replace the loop of arbitrary shape with number of adjacent long, thin, approximately rectangular loops such that we can assume that the distribution of the current is not altered. Then we can prove the relation using the integration method. 2) Formulae: τ = N i A B s i n θ 3) Given: i)Figure 28.19 of rectangular loop ii) The equation for torque acting on the current loop as τ = N i A B s i n θ 4) Calculations: Let us replace the current loop of arbitrary shape with an assembly of thin, adjacent, and small rectangular loops such as to cover the same area enclosed by the original loop. We can assume that each rectangular loop carries the same current ‘i’ as that flowing through the original loop

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ISBN: 9781118230725

Author: David Halliday, Robert Resnick, Jearl Walker

Publisher: Wiley, John & Sons, Incorporated

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Chapter 28, Problem 53P

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To find:

To prove that the relation τ=NiABsinθ holds for any closed loop of arbitrary shape.

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Chapter 28, Problem 52P

Chapter 28, Problem 54P

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To prove that the relation τ = N i A B s i n θ holds for any closed loop of arbitrary shape.

Solution Summary: The author explains how the equation tau =NiABsintheta can hold for any closed loop of arbitrary shape.

To find:

To prove that the relation τ=NiABsinθ holds for any closed loop of arbitrary shape.

Want to see the full answer?

Chapter 28 Solutions

To prove that the relation τ = N i A B s i n θ holds for any closed loop of arbitrary shape.

Solution Summary: The author explains how the equation tau =NiABsintheta can hold for any closed loop of arbitrary shape.

To find: To prove that the relation τ=NiABsinθ holds for any closed loop of arbitrary shape.

Want to see the full answer?

Chapter 28 Solutions

To find:

To prove that the relation τ=NiABsinθ holds for any closed loop of arbitrary shape.