Explanation 1) Concept: We can find the relation between the frequency and the magnetic field using the relation q v B = m v 2 r . From this, we can solve for the B . We can find the equation for v in terms of f . We substitute the value for v in the formula of kinetic energy to get the kinetic energy of the proton. We use the same relation, i.e., q v B = m v 2 r . This time, we solve for f. We can find the equation for v in terms of f . We substitute the value for v in the formula of kinetic energy to get the kinetic energy of the proton emerging from the cyclotron. 2) Formula: i) q v B = m v 2 r ii) K = 1 2 m v 2 iii) ω = v / r iv) ω = 2 π f 3) Given: i) r = 53.0 c m = 0.53 m ii) f = 12.0 M H z = 12.0 × 10 6 H z iii) B = 1.57 T 4) Calculation: a) We know that q v B = m v 2 r q B = m v r q B m = v r ω = q B m We know that ω = 2 π f 2 π f = q B m B = 2 π f m q B = 2 π × 12.0 × 10 6 × 1.67 × 10 - 27 1.6 × 10 - 19 B = 0.787 T b) K = 1 2 m v 2 We know that v r = o m e g a v r = 2 π f v = 2 π r f K = 1 2 × m × 2 π r f 2 K = 1 2 × 1.67 × 10 - 27 × 2 π × 0.53 × 12 × 10 6 2 K = 1

10th Edition

ISBN: 9781118230725

Author: David Halliday, Robert Resnick, Jearl Walker

Publisher: Wiley, John & Sons, Incorporated

See similar textbooks

Concept explainers

Nuclear interactions

In nature, there are certain rules and standards for an interaction. These interactions are universally accepted. There are four types of interactions:

Question

Chapter 28, Problem 36P

To determine

To find:

a) Magnitude of the magnetic field to achieve resonance

b) Kinetic energy of a proton emerging from the cyclotron

c) The oscillator frequency to achieve resonance

d) Kinetic energy of the emerging proton

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 28, Problem 35P

Chapter 28, Problem 37P

Students have asked these similar questions

No chatgpt pls will upvote

No chatgpt pls

Chapter 28 Solutions

Fundamentals of Physics Extended

Ch. 28 - Prob. 1Q Ch. 28 - Prob. 2Q Ch. 28 - Prob. 3Q Ch. 28 - Prob. 4Q Ch. 28 - In Module 28-2, we discussed a charged particle...Ch. 28 - Figure 28-26 shows crossed uniform electic and...Ch. 28 - Figure 28-27 shows the path of an electron that...Ch. 28 - Figure 28-28 shows the path of an electron in a...Ch. 28 - a In Checkpoint 5, if the dipole moment is rotated...Ch. 28 - Particle round about. Figure 28-29 shows 11 paths...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

a) Magnitude of the magnetic field to achieve resonance b) Kinetic energy of a proton emerging from the cyclotron c) The oscillator frequency to achieve resonance d) Kinetic energy of the emerging proton

Solution Summary: The author explains how they can find the relation between the frequency and the magnetic field using qvB=mv2r.

Concept explainers

To find: a) Magnitude of the magnetic field to achieve resonance b) Kinetic energy of a proton emerging from the cyclotron c) The oscillator frequency to achieve resonance d) Kinetic energy of the emerging proton

Want to see the full answer?

Chapter 28 Solutions

To find:

a) Magnitude of the magnetic field to achieve resonance

b) Kinetic energy of a proton emerging from the cyclotron

c) The oscillator frequency to achieve resonance

d) Kinetic energy of the emerging proton