Concept explainers
(a)
Interpretation: The given cyclic monosaccharide is to be converted into its acyclic form.
Concept introduction: The structural representation of sugar molecule in cyclic form is known as Haworth projection. Sugar molecule that has six-membered-ring is known as pyranose and sugar molecule that has five-membered-ring is called furanose. In Fischer projection formula, the horizontal and vertical line represents the bonds that are present above and below the plane, respectively. The verticals bonds are represented as dashed wedge and horizontal bonds as dark wedge.
(b)
Interpretation: The given cyclic monosaccharide is to be converted into its acyclic form.
Concept introduction: The structural representation of sugar molecule in cyclic form is known as Haworth projection. Sugar molecule that has six-membered-ring is known as pyranose and sugar molecule that has five-membered-ring is called furanose. In Fischer projection formula, the horizontal and vertical line represents the bonds that are present above and below the plane, respectively. The verticals bonds are represented as dashed wedge and horizontal bonds as dark wedge.
(c)
Interpretation: The given cyclic monosaccharide is to be converted into its acyclic form.
Concept introduction: In Fischer projection formula, the horizontal and vertical line represents the bonds that are present above and below the plane, respectively. The verticals bonds are represented as dashed wedge and horizontal bonds as dark wedge.
(d)
Interpretation: The given cyclic monosaccharide is to be converted into its acyclic form.
Concept introduction: The structural representation of sugar molecule in cyclic form is known as Haworth projection. Sugar molecule that has six-membered-ring is known as pyranose and sugar molecule that has five-membered-ring is called furanose. In Fischer projection formula, the horizontal and vertical line represents the bonds that are present above and below the plane, respectively. The verticals bonds are represented as dashed wedge and horizontal bonds as dark wedge.
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Chapter 28 Solutions
ORGANIC CHEMISTRY
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- Can u show the process as to how to get these?arrow_forwardSketch the expected 'H NMR spectra for the following compound. Label all of the H's in the structure and the corresponding signal for the spectra you sketch. Make sure you include the integration value and the splitting pattern for each signal Indicate how many signals you would expect in the 13C NMRarrow_forwardUse IUPAC naming rules to name the following hydrocarbon compounds: CH2-CH3 | a) CH-CH-CH2-CH-CH-CH3 b) | CH2 CH3 | CH3 CH3 \ / C=C H 1 H CH2-CH3 c) d) CH=C-CH3 e) CH3-CH2-CH2-CH=CH-CH3 f) CH2=CH-CH2-CH=CH-CH3 g) CH3-CH2-C = C-CH2-CH3 h)arrow_forward
- Q5 Name the following : a. b. C. d. e.arrow_forward25. Predict the major product of the following reaction. 1 equivalent of each of the starting materials was used. H₂C CH3 CH3 H3C H3C H3C. CH2 + H3C. heat CH3 CH H.C. CH3 H.C H.C CH3 CH CH3 CH3 A B C Earrow_forwardFind chemical structures based on the below information. a) Chemical formula C6H8O Compound is aromatic plus has two 1H NMR peaks that integrated for 3 each that are singlets (it could have more peaks in the 1H NMR b) Chemical Formula: C6H100 Compounds is conjugated 'H NMR has a signal that integrates for 6 and is a doublet IR spectra has a signal at 1730 cm-1arrow_forward
- Jaslev Propose a synthesis of the following starting from benzene and any other reagents and chemicals. No mechanisms are required. Indicate the condition for each step plus the major product for each step. More than two steps are required. Step 1 Step 2 مہد Brarrow_forwardPart C: The line formula for another branched alkane is shown below. i. In the IUPAC system what is the root or base name of this compound? ii. How many alkyl substituents are attached to the longest chain? iii. Give the IUPAC name for this compound.arrow_forwardPart D: Draw the Structural Formula for 4-ethyl-2-methylhexane Part E. Draw the Structural Formula for 1-chloro-3,3-diethylpentane (Chloro = Cl)arrow_forward
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