
Concept explainers
Show the products you would expect to obtain from reaction of glyceryl Trioleate with the following reagents:
(a) Excess Br2 in CH2Cl2
(b) H2/Pd
(c) NaOH/H2O
(d) O3, then Zn/CH3CO2H
(e) LiAlH4, then H3O1
(f) CH3MgBr, then H3O1

a) Excess Br2 in CH2Cl2
Interpretation:
The product expected to be formed when glyceryl trioleate reacts with excess bromine in CH2Cl2 is to be given.
Concept introduction:
When compounds containing more than one olefinic double bond are treated with bromine in excess, addition of bromine to all the olefinic double bonds in the molecule takes place.
To give:
The product expected to be formed when glyceryl trioleate reacts with excess bromine in CH2Cl2.
Answer to Problem 20AP
The product expected to be formed when glyceryl trioleate reacts with excess bromine in CH2Cl2 is
Explanation of Solution
Glyceryl trioleate has three olefinic diuble bonds. When glyceryl trioleate is treated with excess bromine in CH2Cl2 addition of bromine takes place to all the three double bonds in the molecule.
The product expected to be formed when glyceryl trioleate reacts with excess bromine in CH2Cl2 is

b) H2/Pd
Interpretation:
The product expected to be formed when glyceryl trioleate reacts with H2/Pd is to be given.
Concept introduction:
When compounds containing more than one olefinic double bond are treated with H2/Pd, reduction occurs and addition of hydrogen to all the double bonds in the molecule takes place.
To give:
The product expected to be formed when glyceryl trioleate reacts with H2/Pd.
Answer to Problem 20AP
The product expected to be formed when glyceryl trioleate reacts with H2/Pd is
Explanation of Solution
When glyceryl trioleate is treated with H2/Pd, addition of hydrogen takes place to the three double bonds in the molecule to yield a saturated compound.
The product expected to be formed when glyceryl trioleate reacts with H2/Pd is

c) NaOH/H2O
Interpretation:
The products expected to be formed when glyceryl trioleate reacts with NaOH/H2O are to be given.
Concept introduction:
When an oil or fat is treated with aqueous NaOH, the ester linkages in them get hydrolyzed to yield glycerol and sodium salt of the acid.
To give:
The products expected to be formed when glyceryl trioleate reacts with NaOH/H2O.
Answer to Problem 20AP
The products expected to be formed when glyceryl trioleate reacts with NaOH/H2O are given below.
Explanation of Solution
When glyceryl trioleate is treated with aqueous NaOH, the ester linkages in them get hydrolyzed to yield glycerol and sodium oleate.
The products expected to be formed when glyceryl trioleate reacts with NaOH/H2O are given below.

d) O3, then Zn/CH3CO2H
Interpretation:
The products expected to be formed when glyceryl trioleate reacts with O3, then with Zn/CH3COOH are to be given.
Concept introduction:
When a compound with double bond is treated with ozone and then with Zn/ CH3COOH, the double bond gets cleaved and the products have an oxygen atom attached to each carbon originally in the double bond.
To give:
The products expected to be formed when glyceryl trioleate reacts with O3, then with Zn/CH3COOH.
Answer to Problem 20AP
The products expected to be formed when glyceryl trioleate reacts with O3, then with Zn/CH3COOH are given below.
Explanation of Solution
When glyceryl trioleate is treated with O3 and then with Zn/CH3COOH, ozone adds to the three double bonds to yield a triozonide which is cleaved when treated with Zn/CH3COOH to give two different aldehydes as products. The aldehyde carbons are present in a double bond in glyceryl trioleate.
The products expected to be formed when glyceryl trioleate reacts with O3, then with Zn/CH3COOH are given below.

e) LiAlH4, then H3O+
Interpretation:
The products expected to be formed when glyceryl trioleate reacts with LiAlH4, then with H3O+ are to be given.
Concept introduction:
When oils and fats are reduced with LiAlH4, then with H3O+, the eater linkages are reduced to give glycerol and the free acid. Double bonds are not reduced by LiAlH4.
To give:
The products expected to be formed when glyceryl trioleate reacts with LiAlH4, then with H3O+.
Answer to Problem 20AP
The products expected to be formed when glyceryl trioleate reacts with LiAlH4, then with H3O+ are given below.
Explanation of Solution
When glyceryl trioleate is treated with LiAlH4 and then with H3O+ the ester linkages in it are reduced to alcohols. LiAlH4 does not reduce the double bonds in glyceryl trioleate.
The products expected to be formed when glyceryl trioleate reacts with LiAlH4, then with H3O+ are given below.

f) CH3MgBr, then H3O+
Interpretation:
The products expected to be formed when glyceryl trioleate reacts with CH3MgBr, then with H3O+ are to be given.
Concept introduction:
Esters when treated with a Grignard reagent and then with H3O+, react with two equivalents of the Grignard reagent to yield a tertiary alcohol. In oils and fats addition of Grignard reagent will take place to all the three carbonyl groups in the ester.
To give:
The products expected to be formed when glyceryl trioleate reacts with CH3MgBr, then with H3O+.
Answer to Problem 20AP
The products expected to be formed when glyceryl trioleate reacts with CH3MgBr, then with H3O+ are given below.
Explanation of Solution
When glyceryl trioleate is treated with CH3MgBr, addition to carbonyl carbons takes place. The addition product when hydrolyzed with H3O+ yields three equivalents of a tertiary alcohol and glycerol as products.
The products expected to be formed when glyceryl trioleate reacts with CH3MgBr, then with H3O+ are given below.
Want to see more full solutions like this?
Chapter 27 Solutions
Organic Chemistry
Additional Science Textbook Solutions
Genetics: From Genes to Genomes
Physical Universe
Campbell Biology (11th Edition)
General, Organic, and Biological Chemistry - 4th edition
- The statements in the tables below are about two different chemical equilibria. The symbols have their usual meaning, for example AG stands for the standard Gibbs free energy of reaction and K stands for the equilibrium constant. In each table, there may be one statement that is faise because it contradicts the other three statements. If you find a false statement, check the box next to t Otherwise, check the "no false statements" box under the table. statement false? AG"1 no false statements: statement false? AG-0 0 InK-0 0 K-1 0 AH-TAS no false statements 2arrow_forwardComplete the following esterification reactions by drawing the line formulas of the carboxylic acid and alcohol required to form the ester shown. catalyst catalyst catalyst apricot fragrancearrow_forwardShow the saponification products of the following ester: You don't need to draw in the Na+ cation. catalyst, A catalyst, A catalyst, Aarrow_forward
- What would happen if the carboxylic acid and alcohol groups were on the same molecule? In essence, the molecule reacts with itself. Draw the structure of the products formed in this manner using the reactants below. If two functional groups interact with one another on the same molecule, this is called an “intramolecular" (within one) rather than "intermolecular" (between two or more) attack. OH OH catalyst OH HO catalyst catalyst HO OHarrow_forwardQ3: Write in the starting alkyl bromide used to form the following products. Include any reactants, reagents, and solvents over the reaction arrow. If more than one step is required, denote separate steps by using 1), 2), 3), etc. H OH racemic OH OH 5 racemicarrow_forwardDraw the Lewis structure of the SO3-O(CH3)2 complex shown in the bottom right of slide 2in lecture 3-3 (“Me” means a CH3 group) – include all valence electron pairs and formal charges.From this structure, should the complex be a stable molecule? Explain.arrow_forward
- please add appropriate arrows, and tell me clearly where to add arrows, or draw itarrow_forwardWhat I Have Learned Directions: Given the following reaction and the stress applied in each reaction, answer the question below. A. H2(g) + Cl2(g) 2 HCl(g) Stress applied: Decreasing the pressure 1. What is the Keq expression? 2. What will be the effect in the number of moles of HCl(g)? 3. What will be the Equilibrium Shift or the reaction? B. Fe3O4(s) + 4 H2(g) + heat 53 Fe(s) + 4 H₂O(g) Stress applied: Increasing the temperature 1. What is the Keq expression?. 2. What will be the effect in the volume of water vapor collected? 3. What will be the Equilibrium Shift or the reaction? C. 4 NH3(g) + 5 O2(g) 4 NO(g) + 6 H2O(g) + heat Stress applied: Increasing the volume of the container 1. What is the Keq expression?. 2. What will be the effect in the amount of H₂O? 3. What will be the Equilibrium Shift or the reaction?arrow_forwardConsider the solubility products (Ksp values) for the following compounds:SrSO4 (Ksp = 7.6 x 10−7), BaSO4 (Ksp = 1.5 x 10−9), SrCO3 (Ksp = 7.0 x 10−10), BaCO3 (Ksp = 1.6 x 10−9)Which anion is the harder base, CO32− or SO42−? Justify your answer.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning

