Study Guide with Student Solutions Manual for McMurry's Organic Chemistry, 9th
9th Edition
ISBN: 9781305082144
Author: John E. McMurry
Publisher: Cengage Learning
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Textbook Question
Chapter 27.SE, Problem 18AP
Fats can be either optically active or optically inactive, depending on their structure. Draw the structure of an optically active fat that yields 2 equivalents of stearic acid and 1 equivalent of oleic acid on hydrolysis. Draw the structure of an optically inactive fat that yields the same products.
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Chapter 27 Solutions
Study Guide with Student Solutions Manual for McMurry's Organic Chemistry, 9th
Ch. 27.1 - Carnauba wax, used in floor and furniture...Ch. 27.1 - Draw structures of glyceryl tripalmitate and...Ch. 27.2 - Prob. 3PCh. 27.2 - Write the saponication reaction of glyceryl...Ch. 27.4 - Prob. 5PCh. 27.5 - Prob. 6PCh. 27.5 - Prob. 7PCh. 27.6 - Draw the following molecules in chair...Ch. 27.6 - Lithocholic acid is an A–B cis steroid found in...Ch. 27.7 - Prob. 10P
Ch. 27.SE - Prob. 11VCCh. 27.SE - Propose a biosynthetic pathway for the...Ch. 27.SE - Identify the following fatty acid, and tell...Ch. 27.SE - Prob. 14MPCh. 27.SE - Prob. 15MPCh. 27.SE - Prob. 16MPCh. 27.SE - Prob. 17APCh. 27.SE - Fats can be either optically active or optically...Ch. 27.SE - Prob. 19APCh. 27.SE - Show the products you would expect to obtain from...Ch. 27.SE - Draw a Newman projection along the C2-C3 bond of...Ch. 27.SE - The plasmalogens are a group of lipids found in...Ch. 27.SE - Prob. 23APCh. 27.SE - Prob. 24APCh. 27.SE - Prob. 25APCh. 27.SE - Prob. 26APCh. 27.SE - Prob. 27APCh. 27.SE - Prob. 28APCh. 27.SE - Prob. 29APCh. 27.SE - Assume that acetyl CoA containing a 14C isotopic...Ch. 27.SE - Assume that acetyl CoA containing a 14C isotopic...Ch. 27.SE - Assume that acetyl CoA containing a 14C isotopic...Ch. 27.SE - Assume that acetyl CoA containing a 14C isotopic...Ch. 27.SE - Prob. 34APCh. 27.SE - Draw the most stable chair conformation of...Ch. 27.SE - Draw the most stable chair conformation of...Ch. 27.SE - Prob. 37APCh. 27.SE - Prob. 38APCh. 27.SE - Prob. 39APCh. 27.SE - What product would you obtain by reduction of...Ch. 27.SE - Prob. 41APCh. 27.SE - Eleostearic acid, C18H30O2, is a rare fatty acid...Ch. 27.SE - Prob. 43APCh. 27.SE - Prob. 44APCh. 27.SE - Propose a synthesis of diethylstilbestrol (Problem...Ch. 27.SE - Prob. 46APCh. 27.SE - Cembrene, C20H32, is a diterpenoid hydrocarbon...Ch. 27.SE - α-Fenchone is a pleasant-smelling terpenoid...Ch. 27.SE - Prob. 49APCh. 27.SE - Propose a mechanism for the biosynthesis of the...
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- Shown below is the major resonance structure for a molecule. Draw the second best resonance structure of the molecule. Include all non-zero formal charges. H. H. +N=C H H H Cl: Click and drag to start drawing a structure. : ? g B S olo Ar B Karrow_forwardDon't used hand raitingarrow_forwardS Shown below is the major resonance structure for a molecule. Draw the second best resonance structure of the molecule. Include all non-zero formal charges. H H = HIN: H C. :0 H /\ H H Click and drag to start drawing a structure. ×arrow_forward
- Part II. two unbranched ketone have molecular formulla (C8H100). El-ms showed that both of them have a molecular ion peak at m/2 =128. However ketone (A) has a fragment peak at m/2 = 99 and 72 while ketone (B) snowed a fragment peak at m/2 = 113 and 58. 9) Propose the most plausible structures for both ketones b) Explain how you arrived at your conclusion by drawing the Structures of the distinguishing fragments for each ketone, including their fragmentation mechanisms.arrow_forwardPart V. Draw the structure of compound tecla using the IR spectrum Cobtained from the compound in KBr pellet) and the mass spectrum as shown below. The mass spectrum of compound Tesla showed strong mt peak at 71. TRANSMITTANCE LOD Relative Intensity 100 MS-NW-1539 40 20 80 T 44 55 10 15 20 25 30 35 40 45 50 55 60 65 70 75 m/z D 4000 3000 2000 1500 1000 500 HAVENUMBERI-11arrow_forwardTechnetium is the first element in the periodic chart that does not have any stable isotopes. Technetium-99m is an especially interesting and valuable isotope as it emits a gamma ray with a half life ideally suited for medical tests. It would seem that the decay of technetium should fit the treatment above with the result In(c/c) = -kt. The table below includes data from the two sites: http://dailymed.nlm.nih.gov/dailymed/druginfo.cfm?id=7130 http://wiki.medpedia.com/Clinical: Neutrospec_(Technetium_(99m Tc)_fanolesomab). a. b. C. Graph the fraction (c/c.) on the vertical axis versus the time on the horizontal axis. Also graph In(c/c.) on the vertical axis versus time on the horizontal axis. When half of the original amount of starting material has hours fraction remaining disappeared, c/c = ½ and the equation In(c/c.) = -kt becomes In(0.5) = -kt1/2 where t₁₂ is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c.) vs t graph and…arrow_forward
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