Technetium is the first element in the periodic chart that does not have any stable isotopes. Technetium-99m is an especially interesting and valuable isotope as it emits a gamma ray with a half life ideally suited for medical tests. It would seem that the decay of technetium should fit the treatment above with the result In(c/c) = -kt. The table below includes data from the two sites: http://dailymed.nlm.nih.gov/dailymed/druginfo.cfm?id=7130 http://wiki.medpedia.com/Clinical: Neutrospec_(Technetium_(99m Tc)_fanolesomab). a. b. C. Graph the fraction (c/c.) on the vertical axis versus the time on the horizontal axis. Also graph In(c/c.) on the vertical axis versus time on the horizontal axis. When half of the original amount of starting material has hours fraction remaining disappeared, c/c = ½ and the equation In(c/c.) = -kt becomes In(0.5) = -kt1/2 where t₁₂ is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c.) vs t graph and calculate the half life of technetium-99m. Compare your value to a literature or Internet value for the half life. Name some of the medical tests that utilize technetium-99m. Explain why technetium-99m is used for these applications. 1.000 0.891 0.794 0.708 0.631 0.562 0.501 0.447 0.398 0.355 0.316 11 0.282 0.251 0.13 0123456789028

Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Mark S. Cracolice, Ed Peters
Chapter20: Nuclear Chemistry
Section: Chapter Questions
Problem 65E
icon
Related questions
Question
100%
Technetium is the first element in the periodic chart that does not have any stable isotopes.
Technetium-99m is an especially interesting and valuable isotope as it emits a gamma ray with a half
life ideally suited for medical tests. It would seem that the decay of technetium should fit the
treatment above with the result In(c/c) = -kt. The table below includes data from the two sites:
http://dailymed.nlm.nih.gov/dailymed/druginfo.cfm?id=7130
http://wiki.medpedia.com/Clinical: Neutrospec_(Technetium_(99m Tc)_fanolesomab).
a.
b.
C.
Graph the fraction (c/c.) on the vertical axis versus the time on the horizontal axis. Also
graph In(c/c.) on the vertical axis versus time on the horizontal axis.
When half of the original amount of starting material has hours fraction remaining
disappeared, c/c = ½ and the equation In(c/c.) = -kt becomes
In(0.5) = -kt1/2 where t₁₂ is the half life (the time for half of the
material to decay away). Determine the slope of your In(c/c.) vs
t graph and calculate the half life of technetium-99m. Compare
your value to a literature or Internet value for the half life.
Name some of the medical tests that utilize technetium-99m.
Explain why technetium-99m is used for these applications.
1.000
0.891
0.794
0.708
0.631
0.562
0.501
0.447
0.398
0.355
0.316
11
0.282
0.251
0.13
0123456789028
Transcribed Image Text:Technetium is the first element in the periodic chart that does not have any stable isotopes. Technetium-99m is an especially interesting and valuable isotope as it emits a gamma ray with a half life ideally suited for medical tests. It would seem that the decay of technetium should fit the treatment above with the result In(c/c) = -kt. The table below includes data from the two sites: http://dailymed.nlm.nih.gov/dailymed/druginfo.cfm?id=7130 http://wiki.medpedia.com/Clinical: Neutrospec_(Technetium_(99m Tc)_fanolesomab). a. b. C. Graph the fraction (c/c.) on the vertical axis versus the time on the horizontal axis. Also graph In(c/c.) on the vertical axis versus time on the horizontal axis. When half of the original amount of starting material has hours fraction remaining disappeared, c/c = ½ and the equation In(c/c.) = -kt becomes In(0.5) = -kt1/2 where t₁₂ is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c.) vs t graph and calculate the half life of technetium-99m. Compare your value to a literature or Internet value for the half life. Name some of the medical tests that utilize technetium-99m. Explain why technetium-99m is used for these applications. 1.000 0.891 0.794 0.708 0.631 0.562 0.501 0.447 0.398 0.355 0.316 11 0.282 0.251 0.13 0123456789028
AI-Generated Solution
AI-generated content may present inaccurate or offensive content that does not represent bartleby’s views.
steps

Unlock instant AI solutions

Tap the button
to generate a solution

Recommended textbooks for you
Introductory Chemistry: An Active Learning Approa…
Introductory Chemistry: An Active Learning Approa…
Chemistry
ISBN:
9781305079250
Author:
Mark S. Cracolice, Ed Peters
Publisher:
Cengage Learning
Chemistry: The Molecular Science
Chemistry: The Molecular Science
Chemistry
ISBN:
9781285199047
Author:
John W. Moore, Conrad L. Stanitski
Publisher:
Cengage Learning
Introductory Chemistry For Today
Introductory Chemistry For Today
Chemistry
ISBN:
9781285644561
Author:
Seager
Publisher:
Cengage
Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
Chemistry
ISBN:
9781337399425
Author:
Steven S. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Principles of Modern Chemistry
Principles of Modern Chemistry
Chemistry
ISBN:
9781305079113
Author:
David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781337399074
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning