Prescott's Microbiology
10th Edition
ISBN: 9781259281594
Author: Joanne Willey, Linda Sherwood Adjunt Professor Lecturer, Christopher J. Woolverton Professor
Publisher: McGraw-Hill Education
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Chapter 27.3, Problem 1MI
Why is the ϕX174 genome considered plus stranded?
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Chapter 27 Solutions
Prescott's Microbiology
Ch. 27.1 - List some characteristics used in classifying...Ch. 27.1 - Consider these terms: Equine torovirus,...Ch. 27.2 - What enzyme found in the T4 baseplate facilitates...Ch. 27.2 - Why do you think T4 evolved to initiate DNA...Ch. 27.2 - What function does HMC glycosylation serve?Ch. 27.2 - How is the envelope of this virus formed? How does...Ch. 27.2 - Explain why the T4 genome is circularly permuted.Ch. 27.2 - Prob. 1.2RIACh. 27.2 - How is a prophage induced to become active again?Ch. 27.2 - Describe the roles of cII, CIII, repressor (CI),...
Ch. 27.2 - How do the temperate phages Mu and P1 differ from...Ch. 27.2 - The CRISPR/Cas system has been a boon to...Ch. 27.2 - Why do cold sores recur throughout the lifetime of...Ch. 27.2 - In what part of the host cell does a herpesvirus...Ch. 27.2 - Many small DNA viruses rely on host enzymes for...Ch. 27.3 - Why is the X174 genome considered plus stranded?Ch. 27.3 - Prob. 2MICh. 27.3 - Why is it necessary for some ssDNA viruses to...Ch. 27.3 - From the point of view of the virus, compare the...Ch. 27.3 - How do parvoviruses trick the host DNA polymerase...Ch. 27.4 - The rotavirus genome encodes 12 proteins. Suggest...Ch. 27.4 - Describe the life cycle of 6 phage. What makes...Ch. 27.4 - Prob. 3RIACh. 27.4 - In what ways are the life cycles of 6 and...Ch. 27.5 - Where in the host does the plus-strand RNA genome...Ch. 27.5 - How do some plus-strand viruses use polyproteins...Ch. 27.5 - What is an IRES? Why is it important?Ch. 27.5 - Prob. 3RIACh. 27.6 - How does that use of a segmented genome by...Ch. 27.6 - Prob. 2RIACh. 27.7 - Prob. 1MICh. 27.7 - Prob. 1RIACh. 27.7 - Prob. 2RIACh. 27.7 - What role does alternative splicing play in the...Ch. 27.8 - Prob. 1RIACh. 27.8 - Trace the HBV multiplication cycle, paying...Ch. 27 - No temperate RNA phages have yet been discovered....Ch. 27 - The choice between lysogeny and lysis is...Ch. 27 - Prob. 3CHICh. 27 - You are studying RNA viruses and have discovered a...Ch. 27 - Prob. 5CHICh. 27 - Upon infection of host epithelial cells,...Ch. 27 - Associated with the envelope of herpesviruses are...
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- You implant an FGF10-coated bead into the anterior flank of a chicken embryo, directly below the level of the wing bud. What is the phenotype of the resulting ectopic limb? Briefly describe the expected expression domains of 1) Shh, 2) Tbx4, and 3) Tbx5 in the resulting ectopic limb bud.arrow_forwardDesign a grafting experiment to determine if limb mesoderm determines forelimb / hindlimb identity. Include the experiment, a control, and an interpretation in your answer.arrow_forwardThe Snapdragon is a popular garden flower that comes in a variety of colours, including red, yellow, and orange. The genotypes and associated phenotypes for some of these flowers are as follows: aabb: yellow AABB, AABb, AaBb, and AaBB: red AAbb and Aabb: orange aaBB: yellow aaBb: ? Based on this information, what would the phenotype of a Snapdragon with the genotype aaBb be and why? Question 21 options: orange because A is epistatic to B yellow because A is epistatic to B red because B is epistatic to A orange because B is epistatic to A red because A is epistatic to B yellow because B is epistatic to Aarrow_forward
- A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardA sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forward
- With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forward
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