Organic Chemistry, Books a la Carte Edition (8th Edition)
8th Edition
ISBN: 9780134074580
Author: Bruice, Paula Yurkanis
Publisher: PEARSON
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Chapter 27, Problem 44P
The
- a. Propose a mechanism for the formation of the copolymer.
- b. Explain why hydrolysis of the copolymer to form the polymer occurs much more rapidly than hydrolysis of para-nitrophenyl acetate.
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Place the following characteristics into the box for the correct ion. Note that some of the characteristics will not be placed in either bin. Use your periodic table
for assistance.
Link to Periodic Table
Drag the characteristics to their respective bins.
▸ View Available Hint(s)
This anion could form a neutral
compound by forming an ionic bond
with one Ca²+.
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This ion forms ionic bonds with
nonmetals.
This ion has a 1- charge.
This is a polyatomic ion.
The neutral atom from which this ion
is formed is a metal.
The atom from which this ion is
formed gains an electron to become
an ion.
The atom from which this ion is
formed loses an electron to become
an ion.
This ion has a total of 18 electrons.
This ion has a total of 36 electrons.
This ion has covalent bonds and a net
2- charge.
This ion has a 1+ charge.
Potassium ion
Bromide ion
Sulfate ion
U
Consider the following graph containing line plots for the moles of Product 1 versus time (minutes) and the moles of Product 2 versus time in minutes.
Choose all of the key terms/phrases that describe the plots on this graph.
Check all that apply.
▸ View Available Hint(s)
Slope is zero.
More of Product 1 is obtained in 12 minutes.
Slope has units of moles per minute.
plot of minutes versus moles
positive relationship between moles and minutes
negative relationship between moles and minutes
Slope has units of minutes per moles.
More of Product 2 is obtained in 12 minutes.
can be described using equation y = mx + b
plot of moles versus minutes
y-intercept is at (12,10).
y-intercept is at the origin.
Product Amount
(moles)
Product 1
B (12,10)
Product 2
E
1
Time
(minutes)
A (12,5)
Solve for x, where M is molar and s is seconds.
x = (9.0 × 10³ M−². s¯¹) (0.26 M)³
Enter the answer. Include units. Use the exponent key above the answer box to indicate any exponent on your units.
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ΜΑ
0
?
Units
Value
Chapter 27 Solutions
Organic Chemistry, Books a la Carte Edition (8th Edition)
Ch. 27.3 - Prob. 1PCh. 27.3 - Prob. 2PCh. 27.3 - Prob. 3PCh. 27.3 - Prob. 4PCh. 27.3 - Prob. 5PCh. 27.3 - Prob. 6PCh. 27.4 - Prob. 7PCh. 27.5 - Rank the following groups of monomers from most...Ch. 27.5 - Why does methyl methacrylate not undergo cationic...Ch. 27.6 - Prob. 10P
Ch. 27.6 - Explain why, when propylene oxide undergoes...Ch. 27.6 - Which monomer and which type of initiator can you...Ch. 27.6 - Prob. 13PCh. 27.8 - Draw a short segment of gutta-percha.Ch. 27.8 - Prob. 15PCh. 27.11 - Prob. 16PCh. 27.11 - Write an equation that explains what happens if a...Ch. 27.11 - What happens to polyester slacks if aqueous NaOH...Ch. 27.11 - a. Propose a mechanism for the formation of the...Ch. 27.11 - Explain why, when a small amount of glycerol is...Ch. 27.12 - Propose a mechanism for the formation of melmac.Ch. 27.12 - Prob. 22PCh. 27.13 - Prob. 23PCh. 27 - Draw short segments of the polymers obtained from...Ch. 27 - Prob. 25PCh. 27 - Prob. 26PCh. 27 - Draw the structure of the monomer or monomers used...Ch. 27 - Prob. 28PCh. 27 - Draw short segments of the polymers obtained from...Ch. 27 - Quiana is a synthetic fabric that feels very much...Ch. 27 - Prob. 31PCh. 27 - Prob. 32PCh. 27 - Prob. 33PCh. 27 - Poly(vinyl alcohol) is a polymer used to make...Ch. 27 - Five different repeating units are found in the...Ch. 27 - Prob. 37PCh. 27 - A particularly strong and rigid polyester used for...Ch. 27 - Prob. 39PCh. 27 - Which Monomer gives a greater yield of polymer,...Ch. 27 - Prob. 41PCh. 27 - Prob. 42PCh. 27 - Why do vinyl raincoats become brittle as they get...Ch. 27 - The polymer shown below is synthesized by...Ch. 27 - Prob. 45PCh. 27 - How can head-to-head poly(vinyl bromide) be...Ch. 27 - Delrin (polyoxymethylene) is a tough...
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- Learning Goal: This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this: 35 Cl 17 In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is: It is also correct to write symbols by leaving off the atomic number, as in the following form: atomic number mass number Symbol 35 Cl or mass number Symbol This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written. Watch this video to review the format for written symbols. In the following table each column…arrow_forwardneed help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal…arrow_forwardneed help please and thanks dont understand only need help with C-F Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal…arrow_forward
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