Organic Chemistry, Books a la Carte Edition (8th Edition)
8th Edition
ISBN: 9780134074580
Author: Bruice, Paula Yurkanis
Publisher: PEARSON
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Chapter 27, Problem 38P
A particularly strong and rigid polyester used for electronic parts is marketed under the trade name Glyptal. It is a
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Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Chapter 27 Solutions
Organic Chemistry, Books a la Carte Edition (8th Edition)
Ch. 27.3 - Prob. 1PCh. 27.3 - Prob. 2PCh. 27.3 - Prob. 3PCh. 27.3 - Prob. 4PCh. 27.3 - Prob. 5PCh. 27.3 - Prob. 6PCh. 27.4 - Prob. 7PCh. 27.5 - Rank the following groups of monomers from most...Ch. 27.5 - Why does methyl methacrylate not undergo cationic...Ch. 27.6 - Prob. 10P
Ch. 27.6 - Explain why, when propylene oxide undergoes...Ch. 27.6 - Which monomer and which type of initiator can you...Ch. 27.6 - Prob. 13PCh. 27.8 - Draw a short segment of gutta-percha.Ch. 27.8 - Prob. 15PCh. 27.11 - Prob. 16PCh. 27.11 - Write an equation that explains what happens if a...Ch. 27.11 - What happens to polyester slacks if aqueous NaOH...Ch. 27.11 - a. Propose a mechanism for the formation of the...Ch. 27.11 - Explain why, when a small amount of glycerol is...Ch. 27.12 - Propose a mechanism for the formation of melmac.Ch. 27.12 - Prob. 22PCh. 27.13 - Prob. 23PCh. 27 - Draw short segments of the polymers obtained from...Ch. 27 - Prob. 25PCh. 27 - Prob. 26PCh. 27 - Draw the structure of the monomer or monomers used...Ch. 27 - Prob. 28PCh. 27 - Draw short segments of the polymers obtained from...Ch. 27 - Quiana is a synthetic fabric that feels very much...Ch. 27 - Prob. 31PCh. 27 - Prob. 32PCh. 27 - Prob. 33PCh. 27 - Poly(vinyl alcohol) is a polymer used to make...Ch. 27 - Five different repeating units are found in the...Ch. 27 - Prob. 37PCh. 27 - A particularly strong and rigid polyester used for...Ch. 27 - Prob. 39PCh. 27 - Which Monomer gives a greater yield of polymer,...Ch. 27 - Prob. 41PCh. 27 - Prob. 42PCh. 27 - Why do vinyl raincoats become brittle as they get...Ch. 27 - The polymer shown below is synthesized by...Ch. 27 - Prob. 45PCh. 27 - How can head-to-head poly(vinyl bromide) be...Ch. 27 - Delrin (polyoxymethylene) is a tough...
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- Please correct answer and don't used hand raitingarrow_forwardneed help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal energy Divide the…arrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Please correct answer and don't used hand raitingarrow_forwardCan you tell me if my answers are correctarrow_forwardBunsenite (NiO) crystallizes like common salt (NaCl), with a lattice parameter a = 4.177 Å. A sample of this mineral that has Schottky defects that are not supposed to decrease the volume of the material has a density of 6.67 g/cm3. What percentage of NiO molecules is missing? (Data: atomic weight of Ni: 58.7; atomic weight of O: 16).arrow_forward
- A sample of aluminum (face-centered cubic - FCC) has a density of 2.695 mg/m3 and a lattice parameter of 4.04958 Å. Calculate the fraction of vacancies in the structure. (Atomic weight of aluminum: 26.981).arrow_forwardPlease correct answer and don't used hand raitingarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Please correct answer and don't used hand raitingarrow_forwardWhich of the following species is a valid resonance structure of A? Use curved arrows to show how A is converted to any valid resonance structure. When a compound is not a valid resonance structurc of A, explain why not. Provide steps and tips on what to look for to understand how to solve and apply to other problems.arrow_forwardN IZ Check the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under the table. Molecule 1 Molecule 2 HN Molecule 3 Х HN www. Molecule 4 Molecule 5 Molecule 6 none of the above NH NH Garrow_forward
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