Concept explainers
Videos
Draw short segments of the
(a)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 24P
The short segment of given monomer is shown below and the monomer undergoes chain growth polymerization.
Explanation of Solution
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a Chain growth polymer because monomer addition occurs at the end of the chain.
(b)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 24P
The short segment of given monomer is shown below and the monomer undergoes chain growth polymerization.
Explanation of Solution
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a Chain growth polymer because monomer addition occurs at the end of the chain.
(c)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 24P
The short segment of given monomer is shown below and the monomer undergoes step growth polymerization.
Explanation of Solution
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a Step growth polymer because monomer addition occurs not at the end of the chain and these polymers are formed by combining monomers by removing small molecules of water or alcohol.
(d)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 24P
The short segment of given monomer is shown below and the monomer undergoes step growth polymerization.
Explanation of Solution
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a step growth polymer because monomer addition occurs not at the end of the chain and these polymers are formed by combining monomers by removing small molecules of water or alcohol.
(e)
Interpretation:
The short segment of polymer obtained from the given monomer has to be drawn and also have to indicate whether it is a chain growth or step growth polymer.
Answer to Problem 24P
The short segment of given monomer is shown below and the monomer undergoes step growth polymerization.
Explanation of Solution
Polymers are formed from linking small units called monomers and they are classified into Chain growth polymers and Step growth polymers.
Given the monomer is
The short segment of polymer obtained from this monomer is given below.
The polymer formed is a Step growth polymer because monomer addition occurs not at the end of the chain and these polymers are formed by combining monomers by removing small molecules of water or alcohol.
Want to see more full solutions like this?
Chapter 27 Solutions
Organic Chemistry, Books a la Carte Edition (8th Edition)
- टे Predict the major products of this organic reaction. Be sure to use wedge and dash bonds when necessary, for example to distinguish between different major products. ☐ ☐ : ☐ + NaOH HO 2 Click and drag to start drawing a structure.arrow_forwardShown below are five NMR spectra for five different C6H10O2 compounds. For each spectrum, draw the structure of the compound, and assign the spectrum by labeling H's in your structure (or in a second drawing of the structure) with the chemical shifts of the corresponding signals (which can be estimated to nearest 0.1 ppm). IR information is also provided. As a reminder, a peak near 1700 cm-1 is consistent with the presence of a carbonyl (C=O), and a peak near 3300 cm-1 is consistent with the presence of an O–H. Extra information: For C6H10O2 , there must be either 2 double bonds, or 1 triple bond, or two rings to account for the unsaturation. There is no two rings for this problem. A strong band was observed in the IR at 1717 cm-1arrow_forwardPredict the major products of the organic reaction below. : ☐ + Х ك OH 1. NaH 2. CH₂Br Click and drag to start drawing a structure.arrow_forward
- NG NC 15Show all the steps you would use to synthesize the following products shown below using benzene and any organic reagent 4 carbons or less as your starting material in addition to any inorganic reagents that you have learned. NO 2 NC SO3H NO2 OHarrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forwardShow work...don't give Ai generated solutionarrow_forward
- 1 Please provide an efficient synthesis of the product below from the starting material. Use the starting material as the ONLY source of carbon atoms. Show the synthesis of each compound that would be used in the overall synthesis of the product. [This synthesis uses alkyne and alcohol chemistry.]arrow_forward10- 4000 20 20 30- %Reflectance 60 50- 09 60- 40- Date: Thu Feb 06 17:30:02 2025 (GMT-05:0(UnknownP Scans: 8 Resolution: 2.000 70 70 88 80 3500 3000 2500 90 100 00 Wavenumbers (cm-1) 2000 1500 2983.10 2359.13 1602.52 1584.22 1451.19 1391.87 1367.07 1314.37 1174.34 1070.13 1027.33 1714.16 1269.47 1000 1106.08 1001.14 937.02 873.60 850.20 780.22 686.91 674.38 643.09 617.98 02/06/25 16:38:20arrow_forwardd. Draw arrow-pushing mechanism for an enzymatic retro-aldol reaction of the following hexose. Use B: and/or HA as needed. OH OH سية HO OH OHarrow_forward
Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning