Chapter 2.6, Problem 6PSA

To determine

To Draw: Conclusion about $\angle SNT$ and $\angle SRT$ .

Answer to Problem 6PSA

  $\angle SNT=\angle SRT$

Explanation of Solution

Given information: $\angle TNR=\angle TRN,\angle NRS=\angle RNS$

Given $\angle TNR=\angle TRN$ .

By addition property,

  $\angle SNT+\angle SNR=\angle SRT+\angle SRN$

But given $\angle SNR=\angle SRN$

  $\begin{array}{l}\therefore \angle SNT+\angle SNR=\angle SRT+\angle SRN\\ \therefore \angle SNT=\angle SRT\end{array}$