Chapter 2, Problem 12RP

To determine

To Calculate: Measure of the larger angle.

Answer to Problem 12RP

The required measure is $\angle A={62}^{\circ }$

Explanation of Solution

Given information: In this question, it is given that one complementary angle has a measure that is six more than twice the other.

Formula used: Here, sum of complementary angles is ${90}^{\circ }$

Calculation: Let both the angles be $\angle A$ and $\angle B$

  $\angle A+\angle B={90}^{\circ }$ (Complementary angles)

Now, According to question:

  $\angle A={62}^{\circ }$

So, $6+2\angle B+\angle B={90}^{\circ }$

  →$3\angle B={84}^{\circ }$

  →$\angle B={28}^{\circ }$

and, $\angle A=6+56$

  →$\angle A={62}^{\circ }$

Hence, the required measure is $\angle A={62}^{\circ }$