Chapter 2, Problem 15RP

To determine

To Calculate: The length of AN.

Answer to Problem 15RP

The required length is $4$ units.

Explanation of Solution

Given information: In this question, it is given that point A is the mid-point of $\overline{DE}$ and DA = $12$ and points I and N are trisection points of $\overline{DE}$

Calculation: Here, DA = $12$

and, DE = $24$

So that, AE = $12$

and, I and N are trisection points of $\overline{DE}$

So that, $\frac{DE}{3}=DI=IN=NE=8$

So, $AE=AN+NE$

  →$12=AN+8$

  $AN=4$

Hence, the required measure is $4$