Chapter 2.1, Problem 6PSA

To determine

To Prove: $\angle 1=\angle 2$

Explanation of Solution

Given information: $a\perp b$

Proof:

  $\begin{array}{l}a\perp b\mathrm{....}(given)\\ \therefore \angle 1={90}^{\circ }\mathrm{....}(\because a\perp b)\mathrm{....}(1)\\ \&\angle 2={90}^{\circ }\mathrm{....}(\because a\perp b)\mathrm{....}(2)\end{array}$

From equation (1) and (2).

  $\angle 1=\angle 2$ (both equal to ${90}^{\circ }$ )