DATA You set up the circuit shown in Fig. 26.22a, where R = 196 Ω. You close the switch at time t = 0 and measure the magnitude i of the current in the resistor R as a function of time t since the switch was closed. Your results are shown in Fig. P26.80 . where you have chosen to plot In i as a function of t . (a) Explain why your data points lie close to a straight line, (b) Use the graph in Fig. P26.80 to calculate the capacitance C and the initial charge Q 0 on the capacitor, (c) When i = 0.0500 A, what is the charge on the capacitor? (d) When q = 0.500 × 10 −4 C, what is the current in the resistor? Figure P26.80
DATA You set up the circuit shown in Fig. 26.22a, where R = 196 Ω. You close the switch at time t = 0 and measure the magnitude i of the current in the resistor R as a function of time t since the switch was closed. Your results are shown in Fig. P26.80 . where you have chosen to plot In i as a function of t . (a) Explain why your data points lie close to a straight line, (b) Use the graph in Fig. P26.80 to calculate the capacitance C and the initial charge Q 0 on the capacitor, (c) When i = 0.0500 A, what is the charge on the capacitor? (d) When q = 0.500 × 10 −4 C, what is the current in the resistor? Figure P26.80
DATA You set up the circuit shown in Fig. 26.22a, where R = 196 Ω. You close the switch at time t = 0 and measure the magnitude i of the current in the resistor R as a function of time t since the switch was closed. Your results are shown in Fig. P26.80. where you have chosen to plot In i as a function of t. (a) Explain why your data points lie close to a straight line, (b) Use the graph in Fig. P26.80 to calculate the capacitance C and the initial charge Q0 on the capacitor, (c) When i = 0.0500 A, what is the charge on the capacitor? (d) When q = 0.500 × 10−4 C, what is the current in the resistor?
1. A charge of -25 μC is distributed uniformly throughout a spherical volume of radius 11.5 cm.
Determine the electric field due to this charge at a distance of (a) 2 cm, (b) 4.6 cm, and (c) 25 cm from
the center of the sphere.
(a) =
=
(b) E =
(c)Ẻ =
=
NC NC NC
1.
A long silver rod of radius 3.5 cm has a charge of -3.9
ис
on its surface. Here ŕ is a unit vector
ст
directed perpendicularly away from the axis of the rod as shown in the figure.
(a) Find the electric field at a point 5 cm from the center of the rod (an outside point).
E =
N
C
(b) Find the electric field at a point 1.8 cm from the center of the rod (an inside point)
E=0
Think & Prepare
N
C
1. Is there a symmetry in the charge distribution? What kind of symmetry?
2. The problem gives the charge per unit length 1. How do you figure out the surface charge density σ
from a?
1. Determine the electric flux through each surface whose cross-section is shown below.
55
S₂
-29
S5
SA
S3
+ 9
Enter your answer in terms of q and ε
Φ
(a) s₁
(b) s₂
=
-29
(C) Φ
զ
Ερ
(d) SA
=
(e) $5
(f) Sa
$6
=
II
✓
-29
S6
+39
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
DC Series circuits explained - The basics working principle; Author: The Engineering Mindset;https://www.youtube.com/watch?v=VV6tZ3Aqfuc;License: Standard YouTube License, CC-BY