Explanation Given info: The electric potential through the parallel combination is 250.0 V and the value of the two capacitors are 6.00 μF and 2.00 μF respectively. Since, the capacitors are in parallel. So, the equivalent capacitance of the parallel connection is, C eq = C 1 + C 2 Here, C eq is the equivalent capacitance of the parallel connection. C 1 is the capacitance of the first capacitor. C 2 is the capacitance of the second capacitor. Substitute 6.00 μF for C 1 and 2.00 μF for C 2 in above equation to find C eq . C eq = 6.00 μF + 2.00 μF =8 .00 μF Thus, the equivalent capacitance of the parallel connection is 8.00 μF . Formula to calculate the charge store in the combination is, Q = C eq V Here, Q is the charge store in the combination. V is the potential through the parallel combination. Substitute 8.00 μF for C eq and 250.0 V for V in above equation to find Q . Q = ( 8.00 μF ( 10 − 6 F 1 μF ) ) ( 250.0 V ) = 2 × 10 − 3 C The charge store in the combination is 2 × 10 − 3 C . The charge store on the capacitor C 1 is, Q 1 = C 1 V Here, Q 1 is the charge store on the capacitor C 1 . Substitute 6.00 μF for C 1 and 250.0 V for V in above equation to find Q 1 . Q 1 = ( 6.00 μF ( 10 − 6 F 1 μF ) ) ( 250.0 V ) = 1.5 × 10 − 3 C Thus, the charge store on the capacitor C 1 is 1.5 × 10 − 3 C . The charge on the capacitor C 2 ( 2.00 μF ) is, Q 2 = Q − Q 1 Here, Q 2 is the charge store on the capacitor C 2 . Substitute 1.5 × 10 − 3 C for Q 1 and 2 × 10 − 3 C for Q in above equation to find Q 2 . Q 2 = 2 × 10 − 3 C − 1.5 × 10 − 3 C =0 .5 × 10 − 3 C The net charge on the capacitor after disconnecting from battery and connected to positive plate and negative plate and negative plate to positive plate is, q = Q 1 − Q 2 Here, q is the net charge on the capacitor after disconnecting from battery. Substitute 0 .5 × 10 − 3 C for Q 2 and 1

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN: 9781305116399

Author: Raymond A. Serway, John W. Jewett

Publisher: Cengage Learning

See similar textbooks

Concept explainers

Combination of Capacitors

The connection of capacitors can be established in a circuit in two ways.

Videos

Question

Chapter 26, Problem 26.69AP

To determine

The resulting charges on each capacitor.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 26, Problem 26.68AP

Chapter 26, Problem 26.70AP

Chapter 26 Solutions

Physics for Scientists and Engineers, Technology Update (No access codes included)

Ch. 26 - A capacitor stores charge Q at a potential...Ch. 26 - Many computer keyboard buttons are constructed of...Ch. 26 - Two capacitors are identical. They can be...Ch. 26 - You have three capacitors and a battery. In which...Ch. 26 - If you have ever tried to hang a picture or a...Ch. 26 - A fully charged parallel-plate capacitor remains...Ch. 26 - By what factor is the capacitance of a metal...Ch. 26 - An electronics technician wishes to construct a...Ch. 26 - A parallel-plate capacitor is connected to a...Ch. 26 - If three unequal capacitors, initially uncharged,...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The resulting charges on each capacitor.

Solution Summary: The author explains the electric potential through the parallel combination is 250.0V and the value of the two capacitors.

Concept explainers

Videos

The resulting charges on each capacitor.

Want to see the full answer?

Chapter 26 Solutions