
(a)
Interpretation:
The elution volume of excluded molecules should be calculated.
Concept introduction:
Molecular exclusion chromatography:
The molecules are separated by its size in chromatographic separation is known as molecular exclusion chromatography.
In this chromatography, the large molecules are eluted first then small molecules are separated.
The elution volume is directly proportional to the molar mass of the molecule so it is called as gel filtration or permeation chromatography.
Hydrophobic interaction chromatography:
The substance, which is repels the water is known as hydrophobic substance. In Hydrophobic interaction chromatography, the stationary phase is hydrophobic substance.
In the chromatography, the molecule is interact with stationary phase of the column and the solubility of molecule, which is going to separate is decreasing salt concentration of reagent ti increasing solubility molecule.
(a)

Explanation of Solution
To calculate the elution volume of excluded molecules.
Given,
Column diameter is
Column length is
Occupation of gel particles is
Occupation of pores is
The volume between particles occupies is
In then affinity column chromatography, only the bonded molecule is remains in the column rest of other are eluted so the eluted volume is equal to the volume used in the elution of excluded molecules.
Total volume of the column is,
The volume of elution of excluded molecules is equal to the
Therefore, the volume of elution volume of excluded molecules is
The elution volume of excluded molecules was calculated.
(b)
Interpretation:
The elution volume of small molecules should be calculated.
Concept introduction:
Molecular exclusion chromatography:
The molecules are separated by its size in chromatographic separation is known as molecular exclusion chromatography.
In this chromatography, the large molecules are eluted first then small molecules are separated.
The elution volume is directly proportional to the molar mass of the molecule so it is called as gel filtration or permeation chromatography.
Hydrophobic interaction chromatography:
The substance, which is repels the water is known as hydrophobic substance. In Hydrophobic interaction chromatography, the stationary phase is hydrophobic substance.
In the chromatography, the molecule is interact with stationary phase of the column and the solubility of molecule, which is going to separate is decreasing salt concentration of reagent ti increasing solubility molecule.
(b)

Explanation of Solution
To calculate the elution volume of excluded molecules.
Given,
Column diameter is
Column length is
Occupation of gel particles is
Occupation of pores is
The volume between particles occupies is
In then affinity column chromatography, only the bonded molecule is remains in the column rest of other are eluted so the eluted volume is equal to the volume used in the elution of excluded molecules.
Total volume of the column is,
The volume of small of excluded molecules is equal to the
Therefore, the volume of elution volume of small molecules is
The elution volume of small molecules was calculated.
(c)
Interpretation:
Elution of polyethylene glycols from polystyrene resin in HPLC should be explained.
Concept introduction:
Molecular exclusion chromatography:
The molecules are separated by its size in chromatographic separation is known as molecular exclusion chromatography.
In this chromatography, the large molecules are eluted first then small molecules are separated.
The elution volume is directly proportional to the molar mass of the molecule so it is called as gel filtration or permeation chromatography.
Hydrophobic interaction chromatography:
The substance, which is repels the water is known as hydrophobic substance. In Hydrophobic interaction chromatography, the stationary phase is hydrophobic substance.
In the chromatography, the molecule is interact with stationary phase of the column and the solubility of molecule, which is going to separate is decreasing salt concentration of reagent ti increasing solubility molecule.
(c)

Explanation of Solution
To calculate the elution volume of excluded molecules.
Given,
Column diameter is
Column length is
Occupation of gel particles is
Occupation of pores is
The volume between particles occupies is
In then affinity column chromatography, only the bonded molecule is remains in the column rest of other are eluted so the eluted volume is equal to the volume used in the elution of excluded molecules.
Total volume of the column is,
The volume of elution of excluded molecules is equal to the
Therefore, the volume of elution volume of excluded molecules is
The volume of small of excluded molecules is equal to the
Therefore, the volume of elution volume of small molecules is
Hence, the solute is absorbed on the polystyrene resin or otherwise they are eluted between
The elution volume of polyethylene glycols are
From the above calculations the given column size and elution volume of column, the molecules are eluted between
Therefore, polyethylene glycols are must adsorbed on the polystyrene resin and they are eluted between
Elution of polyethylene glycols from polystyrene resin in HPLC was explained.
Want to see more full solutions like this?
Chapter 26 Solutions
Quantitative Chemical Analysis 9e And Sapling Advanced Single Course For Analytical Chemistry (access Card)
- Steps and explanation please. Add how to solve or target similar problems.arrow_forwardWould the following organic synthesis occur in one step? Add any missing products, required catalysts, inorganic reagents, and other important conditions. Please include a detailed explanation and drawings showing how the reaction may occur in one step.arrow_forwardThis organic molecule is dissolved in an acidic aqueous solution: OH OH A short time later sensitive infrared spectroscopy reveals the presence of a new C = O stretch absorption. That is, there must now be a new molecule present with at least one C = O bond. In the drawing area below, show the detailed mechanism that could convert the molecule above into the new molecule. Videos 849 Explanation Check C Click and drag to start dwing a structure. # 3 MAR 23 Add/Remove steparrow_forward||| 7:47 ull 57% ← Problem 19 of 48 Submit Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the curved arrows to draw the product of this carbocation rearrangement. Include all lone pairs and charges as appropriate. H 1,2-alkyl shift +arrow_forwardWould the following organic synthesis occur in one step? Add any missing products, required catalysts, inorganic reagents, and other important conditions. Please include a detailed explanation and drawings showing how the reaction may occur in one step.arrow_forwardBelow is the SN1 reaction of (S)-3-chlorocyclohexene and hydroxide (OH). Draw the missing curved arrows, lone pairs of electrons, and nonzero formal charges. In the third box, draw the two enantiomeric products that will be produced. 5th attempt Please draw all four bonds at chiral centers. Draw the two enantiomeric products that will be produced. Draw in any hydrogen at chiral centers. 1000 4th attempt Feedback Please draw all four bonds at chiral centers. 8. R5 HO: See Periodic Table See Hint H Cl Br Jid See Periodic Table See Hintarrow_forwardShow that a molecule with configuration π4 has a cylindrically symmetric electron distribution. Hint: Let the π orbitals be equal to xf and yf, where f is a function that depends only on the distance from the internuclear axis.arrow_forward(a) Verify that the lattice energies of the alkali metal iodides are inversely proportional to the distances between the ions in MI (M = alkali metal) by plotting the lattice energies given below against the internuclear distances dMI. Is the correlation good? Would a better fit be obtained by plotting the lattice energies as a function of (1 — d*/d)/d, as theoretically suggested, with d* = 34.5 pm? You must use a standard graphing program to plot the graph. It generates an equation for the line and calculates a correlation coefficient. (b) From the graph obtained in (a), estimate the lattice energy of silver iodide. (c) Compare the results of (b) with the experimental value of 886 kJ/mol. If they do not agree, explain the deviation.arrow_forwardCan I please get help with #3 & 4? Thanks you so much!arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





