Lab Manual for Tomczyk/Silberstein/ Whitman/Johnson’s Refrigeration and Air Conditioning Technology, 8th
8th Edition
ISBN: 9781305578708
Author: John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson
Publisher: Cengage Learning
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Chapter 26, Problem 16RQ
A(n)_______varies the frequency of an electronically altered sine wave, which affects the speed of alternating current motors.
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14.25.2.5 kg/s of a solution at 288 K
containing 10 per cent of dissolved solids
is fed to a forward-feed double-effect
evaporator, operating at 14 kN/m² in the
last effect. If the product is to consist of
a liquid containing 50 per cent by mass of
dissolved solids and dry saturated steam
is fed to the steam coils, what
PROBLEMS
1179
should be the pressure of the steam? The
surface in each effect is 50 m² and the
coefficients for heat transfer in the first
and second effects are 2.8 and 1.7 kW/
m² K, respectively. It may be assumed
that the concentrated solution exhibits a
boiling-point rise of 5 deg K, that the latent
heat has a constant value of 2260 kJ/kg
and that the specific heat capacity of the
liquid stream is constant at 3.75 kJ/kg K
O
: +0
العنوان
use only
5) A 100 kg batch of granular solids
containing 30% moisture is to be dried in
a tray drier to
15.5% by passing a current of air at 350
K tangentially across its surface at a
velocity of 1.8
m/s. If the constant rate of drying under
these conditions is 0.7 g/s m2
and the critical moisture
content is 15%, calculate the
approximate drying time. Assume the
drying surface to be 0.03
m2
/kg dry mass.
мони
give me solution math not explin
Chapter 26 Solutions
Lab Manual for Tomczyk/Silberstein/ Whitman/Johnson’s Refrigeration and Air Conditioning Technology, 8th
Ch. 26 - The two broad categories of display cases are...Ch. 26 - How are conditions maintained in open display...Ch. 26 - What are mullion heaters?Ch. 26 - The three temperature ranges for refrigeration...Ch. 26 - The two methods for rejecting heat from...Ch. 26 - When the compressors are located in the equipment...Ch. 26 - When one large compressor is used, what desirable...Ch. 26 - Define a parallel compressor system and list five...Ch. 26 - Three disadvantages of parallel compressor systems...Ch. 26 - What is the difference between an even and an...
Ch. 26 - Exactly matching the refrigeration load with the...Ch. 26 - What is the function of the pressure transducer in...Ch. 26 - What is the function of the microprocessor-based...Ch. 26 - Explain how the oil separator, oil reservoir,...Ch. 26 - Large or small compressors on parallel compressor...Ch. 26 - A(n)_______varies the frequency of an...Ch. 26 - Prob. 17RQCh. 26 - Prob. 18RQCh. 26 - Three advantages of unitary, stand-alone...Ch. 26 - How is defrost accomplished when the equipment...Ch. 26 - True or False: The two types of defrosts used with...Ch. 26 - What special precautions should be taken with...Ch. 26 - Prob. 23RQCh. 26 - What special valve is used in a refrigerated air...Ch. 26 - Briefly explain what is meant by a surge-type...Ch. 26 - Briefly explain what is meant by a subcritical...Ch. 26 - Briefly explain what is meant by a transcritical...Ch. 26 - Prob. 28RQCh. 26 - Prob. 29RQCh. 26 - Prob. 30RQCh. 26 - Prob. 31RQCh. 26 - Prob. 32RQCh. 26 - Prob. 33RQ
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- ۲/۱ : +0 العنوان seoni 4) 1 Mg (dry weight) of a non-porous solid is dried under constant drying conditions with an air velocity of 0.75 m/s parallel to the drying surface. The area of drying surface is 55 m2 If initial rate of drying is 0.3 g/m2 s, how long it will take to dry a material from 0.15 to 0.025 kg water/kg dry solid? The critical moisture content is 0.125 and the equilibrium moisture is negligible. The falling rate of drying is linear in moisture content. If air velocity increases to 4 m/s, what will be the anticipated saving in drying time? 0 ostherarrow_forward14.23. A double-effect forward-feed evaporator is required to give a product consisting of 30 per cent crystals and a mother liquor containing 40 per cent by mass of dissolved solids. Heat transfer coefficients are 2.8 and 1.7 kW/m² K in the first and second effects respectively. Dry saturated steam is supplied at 375 kN/m² and the condenser operates at 13.5 kN/ m². (a) What area of heating surface is required in each effect assuming the effects are identical, if the feed rate is 0.6 kg/s of liquor, containing 20 per cent by mass of dissolved solids, and the feed temperature is 313 K? (b) What is the pressure above the boiling liquid in the first effect? The specific heat capacity may be taken as constant at 4.18 kJ/kg K. and the effects of boiling-point rise and of hydrostatic head may be neglected. O Oarrow_forward5) A 100 kg batch of granular solids containing 30% moisture is to be dried in a tray drier to 15.5% by passing a current of air at 350 K tangentially across its surface at a velocity of 1.8 m/s. If the constant rate of drying under these conditions is 0.7 g/s m2 and the critical moisture content is 15%, calculate the approximate drying time. Assume the drying surface to be 0.03 m2 /kg dry mass. Oarrow_forward
- Solve for v and Iarrow_forwardG = 0.350MPa, P = 900N, a=20mm, b=50mm, c=80mmarrow_forward[20 Points] Use Method of Sections to draw the shear-force and bending-moment diagrams for the simply supported beam shown. Determine the maximum bending moment that occurs in the span. 1.5 kN/m 4 m 2 m Carrow_forward
- 14.10. A liquor containing 15 per cent solids is concentrated to 55 per cent solids in a double-effect evaporator. operating at a pressure in the second effect of 18 kN/m². No crystals are formed. The flowrate of feed is 2.5 kg/ s at 375 K with a specific heat capacity of 3.75 kJ/kg K. The boiling-point rise of the concentrated liquor is 6 deg K and the steam fed to the first effect is at 240 kN/ m². The overall heat transfer coefficients in the first and second effects are 1.8 and 0.63 kW/m²K. respectively. If the heat transfer area is to be the same in each effect, what areas should be specified? D Aarrow_forward14.9. A forward feed double-effect vertical evaporator, with equal heating areas in each effect, is fed with 5 kg/s of a liquor of specific heat capacity of 4.18 kJ/kg K. and with no boiling point rise, so that 50 per cent of the feed liquor is evaporated. The overall heat transfer coefficient in the second effect is 75 per cent of that in the first effect. Steam is fed at 395 K and the boiling point in the second effect is 373 K. The feed is heated by an external heater to the boiling point in the first effect. It is decided to bleed off 0.25 kg/s of vapour from the vapour line to the second effect for use in another process. If the feed is still heated to the boiling point of the first effect by external means, what will be the change in steam consumption of the evaporator unit? For the purpose of calculation, the latent heat of the vapours and of the steam may both be taken as 2230 kJ/kg Ад Oarrow_forwardcorrect the shaft misalignment in a cars transmission system, determine the offset distance required to correct the shaft misalignment of 4 degrees in a rotating system. shaft diameter is 4cm.arrow_forward
- 14.14. A three-stage evaporator is fed with 1.25 kg/s of a liquor which is concentrated from 10 to 40 per cent solids by mass. The heat transfer coefficients may be taken as 3.1, 2.5 and 1.7 kW/m² K, respectively, in each effect. Calculate the steam flow at 170 kN/m² and the temperature distribution in the three effects, if: (a) the feed is at 294 K, and (b) the feed is at 355 K. Forward feed is used in each case and the values of U are the same for the two systems. The boiling point in the third effect is 325 K and the liquor has no boiling point rise. Oarrow_forwardForm of the second question 3 Question 2: 500 In the figure shown, gear 2 rotates at 1000rpm. It transmits a power of 5kw to gear 4 via gear Loose 3 idler all gears spur, angle Gear pressure =200, and inclusion = 5m. Draw Analyze the forces on gear 3 and then find the reactions on Column 6, knowing the number of teeth N₂ = 12, N3 = 60, N₁ = 40arrow_forwardExample (7): Determine the heating surface area required for the production of 2.5kg/s of 50wt% NaOH solution from 15 wt% NaOH feed solution which entering at 100 oC to a single effect evaporator. The steam is available as saturated at 451.5K and the boiling point rise (boiling point evaluation) of 50wt% solution is 35K. the overall heat transfer coefficient is 2000 w/m²K. The pressure in the vapor space of the evaporator at atmospheric pressure. The solution has a specific heat of 4.18kJ/ kg.K. The enthalpy of vaporization under these condition is 2257kJ/kg Example (6): 5:48 م An evaporator is concentrating F kg/h at 311K of a 20wt% solution of NaOH to 50wt %. The saturated steam used for heating is at 399.3K. The pressure in the vapor space of the evaporator is 13.3 KPa abs. The 5:48 Oarrow_forward
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