Welding: Principles and Applications (MindTap Course List)
8th Edition
ISBN: 9781305494695
Author: Larry Jeffus
Publisher: Cengage Learning
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Textbook Question
Chapter 25, Problem 3R
Why is it possible to do more than one nondestructive test on a weldment?
Expert Solution & Answer
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=
The forces F₁ = 590 lb, F₂ = 380 lb, F3 = 240 lb and F
330 lb. Determine the forces in each member of the truss.
Use positive values to indicate tension and negative values to
indicate compression.
a
a
a
D
b
F₁
A
000
B.
779977
F₂V
H
G
E
F4
b
BY NC SA
2013 Michael Swanbom
Values for dimensions on the figure are given in the following
table. Note the figure may not be to scale.
Variable Value
a
6 ft
b
10.1 ft
The force in member AB is
lb.
The force in member AH is
lb.
The force in member GH is
lb.
The force in member BH is
lb.
The force in member BC is
lb.
The force in member BG is
lb.
The force in member EG is
lb.
The force in member CD is
lb.
The force in member DE is
lb.
The force in member CE is
lb.
The force in member CG is
lb.
Multiple Choice
Circle the best answer to each statement.
1. Which type of surface deviation is controlled by a cy-
lindricity tolerance but not by a circularity tolerance?
A.
B.
C.
Ovality
Taper
Lobing
D. None of the above
2. When verifying a cylindricity tolerance, the inspec-
tion method must be able to collect a set of points and
determine the:
A. Distance between two coaxial cylinders that con-
tain the set of points
B.
Cylinder that circumscribes the set of points
C. Cylinder that inscribes the set of points
D.
Distance between two coaxial circles that contain
the set of points
3. Where Rule #1 applies to a cylindrical regular feature
of size, the tolerance value of a cylindricity tolerance
applied to the feature of size must be
tolerance.
A. Less than
B. Equal to
C. Greater than
D. None of the above
the size
4. Which of the following modifiers may be applied with
a cylindricity tolerance?
A. M
B.
C. ℗
D. Ø
5. Which geometric tolerance can provide an indirect
cylindricity…
The beam AB is attached to the wall in the xz plane by a
fixed support at A. A force of
F = (−129î + 69.0ĵ + 3591) N is applied to the end of
the beam at B. The weight of the beam can be modeled with
a uniform distributed load of intensity w = 85.0 N/m acting in
the negative z direction along its entire length. Find the
support reactions at A.
Z
с
A
b
a
B
F
y
Cc 10
BY NC SA
2016 Eric Davishahl
X
Values for dimensions on the figure are given in the following.
table. Note the figure may not be to scale.
Variable
Value
a
5.60 m
b
5.00 m
C
3.70 m
A
II
=
MA = (
m
2.>
~.>
+
+
k) N
k) N-
Chapter 25 Solutions
Welding: Principles and Applications (MindTap Course List)
Ch. 25 - Why are all welds not inspected to the same level...Ch. 25 - Why is the strength of all production parts not...Ch. 25 - Why is it possible to do more than one...Ch. 25 - What is a discontinuity?Ch. 25 - What is a defect?Ch. 25 - What is tolerance?Ch. 25 - What are the 12 most common discontinuities?Ch. 25 - How can porosity form in a weld and not be seen by...Ch. 25 - What welding process can cause porosity to form?Ch. 25 - How is piping porosity formed?
Ch. 25 - What are inclusions, and how are they caused?Ch. 25 - When does inadequate joint penetration usually...Ch. 25 - How can a notch cause incomplete fusion?Ch. 25 - How can an arc strike appear on a guided-bend...Ch. 25 - What is overlap?Ch. 25 - What is undercut?Ch. 25 - What causes crater cracks?Ch. 25 - What is underfill?Ch. 25 - What is the difference between a lamination and a...Ch. 25 - How can stress be reduced through a plate's...Ch. 25 - What would be the tensile strength in pounds per...Ch. 25 - What would be the elongation for a specimen for...Ch. 25 - How are the results of a stress test reported?Ch. 25 - What would be the transverse shear strength per...Ch. 25 - What would be the longitudinal shearing strength...Ch. 25 - What are the three methods of destructive testing...Ch. 25 - How are the specimens bent for a guided-. root-,...Ch. 25 - How wide should a specimen be if the material...Ch. 25 - Why are guidelines drawn on the surface of a...Ch. 25 - What part of a fillet weld break test is examined?Ch. 25 - What can happen if acids are handled carelessly?Ch. 25 - What information about the weld does an impact...Ch. 25 - Which nondestructive test is most commonly used?Ch. 25 - List the five steps to be followed when using a...Ch. 25 - What properties must metal have before it can be...Ch. 25 - Why will some flaws appear larger on an X-ray than...Ch. 25 - How is the size of a flaw determined using...Ch. 25 - What is the major limitation of eddy current...Ch. 25 - What information does a hardness test reveal?Ch. 25 - Why is it important to select the correct welding...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- need help?arrow_forwardA bent pipe is attached to a wall with brackets as shown. A force of F = 180 lb is applied to the end of the tube with direction indicated by the dimensions in the figure. Determine the support reactions at the brackets B, C, and D. Model these brackets as journal bearings (only force reactions perpendicular to the axis of the tube) and neglect couple moment reactions. Assume the distance between the supports at B and C and the tube bends nearby are negligible such that the support at C is directly above the support at D and the dimension g gives the distance between supports B and C. Enter your answers in Cartesian components. 2013 Michael Swanbom cc 10 BY NC SA g h א B 8° У A C x каж Values for dimensions on the figure are given in the table below. Note the figure may not be to scale. Variable Value a 6.72 in b 11.8 in с 14.8 in d 42.0 in h 26.6 in g 28.0 in → The reaction at B is B = lb. The reaction at C is C = lb. The reaction at D is D = lb. + << + + 2. + + 557 〈んarrow_forwardThe force F1 = 10 kN, F2 = 10 kN, F3 = 10 kN, F4 = 5 KN are acting on the sttructure shown. Determine the forces in the members specified below. Use positive values to indicate tension and negative values to indicate compression. F2 D b F1 F3 C E b F4 b B F a G Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 3 m b 4 m The force in member BC is KN. The force in member BE is KN. The force in member EF is KN.arrow_forward
- h = The transmission tower is subjected to the forces F₁ 3.6 KN at 50° and F2 = 3.3 kN at = 35°. Determine the forces in members BC, BP, PQ, PC, CD, DP and NP. Use positive values to indicate tension and negative values to indicate compression. 不 кажаж в *а*аж E N M d d IF, c B CENTER LINE S อ K F₂ Kbb cc 10 BY NC SA 2013 Michael Swanbom Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 1.7 m b 4.9 m с 3 m d 5.2 m h 8.4 m Values for dimensions on the figure are given in the following table. Note the figure may not be to scale. Variable Value a 1.7 m 4.9 m с 3 m d 5.2 m h 8.4 m The force in member BC is KN. The force in member BP is KN. The force in member PQ is KN. The force in member PC is KN. The force in member CD is KN. The force in member DP is KN. The force in member NP is KN.arrow_forwardنصاف Sheet Asteel bar of rectangular cross section with dimension Shown in fig. below. This bar is as Connected toawell. Using welded Join a long the sides als only find the weld size (h). Where: Tall = 35 MN/M² F=213.30 answer/h= 4.04 ☐ Yomm Soomm 100mmarrow_forwardFEAarrow_forward
- FEAarrow_forwardHELP?arrow_forwardTrue and False Indicate if each statement is true or false. T/F 1. Rule #1 protects the function of assembly. T/F 2. One of the fundamental dimensioning rules requires all dimensions apply in the free-state condition for rigid parts. T/F 3. The fundamental dimensioning rules that apply on a drawing must be listed in the general notes. T/F 4. Where Rule #1 applies to a drawing, it limits the form of every feature of size on the drawing. T/F 5. Rule #1 limits the variation between features of size on a part. T/F 6. The designer must specify on the drawing which features of size use Rule #1. T/F T/F T/F 7. Rule #1 applies to nonrigid parts (in the unrestrained state). 8. A GO gage is a fixed-limit gage. 9. Rule #1 requires that the form of an individual regular feature of size is controlled by its limits of sizearrow_forward
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