Welding: Principles and Applications (MindTap Course List)
8th Edition
ISBN: 9781305494695
Author: Larry Jeffus
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 25, Problem 1R
Why are all welds not inspected to the same level or standard?
Expert Solution & Answer
To determine
The reason all welds are not inspected to the same level or standard.
Answer to Problem 1R
The quality of the weld that will pass or be acceptable for one welding application may not meet the needs of another.
Explanation of Solution
Given Information:
All welds are not inspected to same level or standard.
All welds are not inspected to the same level. The required quality of welds depends on the service which the object provides.
A high-quality weld is required in nuclear reactors, while a moderate quality of weld may work for house window.
So, the inspection of welds for nuclear reactor should higher the standards, but same standard for welds of house window will not be needed. Therefore, all the welds are not inspected to the same level or standard, rather it depends on the service of the object.
Want to see more full solutions like this?
Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
500
Q3: The attachment shown in Fig.3 is made of
1040 HR. The static force is 30 kN. Specify the
weldment (give the pattern, electrode
number, type of weld, length of weld, and leg
size).
Fig. 3
All dimension
in mm
30 kN
100
(10 Marks)
(read image) (answer given)
A cylinder and a disk are used as pulleys, as shown in the figure. Using the data
given in the figure, if a body of mass m = 3 kg is released from rest after falling a
height h 1.5 m, find:
a) The velocity of the body.
b) The angular velocity of the disk.
c) The number of revolutions the cylinder has made.
T₁
F
Rd =
0.2 m
md =
2 kg
T
T₂1
Rc = 0.4 m
mc = 5 kg
☐ m = 3 kg
Chapter 25 Solutions
Welding: Principles and Applications (MindTap Course List)
Ch. 25 - Why are all welds not inspected to the same level...Ch. 25 - Why is the strength of all production parts not...Ch. 25 - Why is it possible to do more than one...Ch. 25 - What is a discontinuity?Ch. 25 - What is a defect?Ch. 25 - What is tolerance?Ch. 25 - What are the 12 most common discontinuities?Ch. 25 - How can porosity form in a weld and not be seen by...Ch. 25 - What welding process can cause porosity to form?Ch. 25 - How is piping porosity formed?
Ch. 25 - What are inclusions, and how are they caused?Ch. 25 - When does inadequate joint penetration usually...Ch. 25 - How can a notch cause incomplete fusion?Ch. 25 - How can an arc strike appear on a guided-bend...Ch. 25 - What is overlap?Ch. 25 - What is undercut?Ch. 25 - What causes crater cracks?Ch. 25 - What is underfill?Ch. 25 - What is the difference between a lamination and a...Ch. 25 - How can stress be reduced through a plate's...Ch. 25 - What would be the tensile strength in pounds per...Ch. 25 - What would be the elongation for a specimen for...Ch. 25 - How are the results of a stress test reported?Ch. 25 - What would be the transverse shear strength per...Ch. 25 - What would be the longitudinal shearing strength...Ch. 25 - What are the three methods of destructive testing...Ch. 25 - How are the specimens bent for a guided-. root-,...Ch. 25 - How wide should a specimen be if the material...Ch. 25 - Why are guidelines drawn on the surface of a...Ch. 25 - What part of a fillet weld break test is examined?Ch. 25 - What can happen if acids are handled carelessly?Ch. 25 - What information about the weld does an impact...Ch. 25 - Which nondestructive test is most commonly used?Ch. 25 - List the five steps to be followed when using a...Ch. 25 - What properties must metal have before it can be...Ch. 25 - Why will some flaws appear larger on an X-ray than...Ch. 25 - How is the size of a flaw determined using...Ch. 25 - What is the major limitation of eddy current...Ch. 25 - What information does a hardness test reveal?Ch. 25 - Why is it important to select the correct welding...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- (read image) (answer given)arrow_forward11-5. Compute all the dimensional changes for the steel bar when subjected to the loads shown. The proportional limit of the steel is 230 MPa. 265 kN 100 mm 600 kN 25 mm thickness X Z 600 kN 450 mm E=207×103 MPa; μ= 0.25 265 kNarrow_forwardT₁ F Rd = 0.2 m md = 2 kg T₂ Tz1 Rc = 0.4 m mc = 5 kg m = 3 kgarrow_forward
- 2. Find a basis of solutions by the Frobenius method. Try to identify the series as expansions of known functions. (x + 2)²y" + (x + 2)y' - y = 0 ; Hint: Let: z = x+2arrow_forward1. Find a power series solution in powers of x. y" - y' + x²y = 0arrow_forward3. Find a basis of solutions by the Frobenius method. Try to identify the series as expansions of known functions. 8x2y" +10xy' + (x 1)y = 0 -arrow_forward
- Hello I was going over the solution for this probem and I'm a bit confused on the last part. Can you please explain to me 1^4 was used for the Co of the tubular cross section? Thank you!arrow_forwardBlood (HD = 0.45 in large diameter tubes) is forced through hollow fiber tubes that are 20 µm in diameter.Equating the volumetric flowrate expressions from (1) assuming marginal zone theory and (2) using an apparentviscosity for the blood, estimate the marginal zone thickness at this diameter. The viscosity of plasma is 1.2 cParrow_forwardQ2: Find the shear load on bolt A for the connection shown in Figure 2. Dimensions are in mm Fig. 2 24 0-0 0-0 A 180kN (10 Markarrow_forward
- determine the direction and magnitude of angular velocity ω3 of link CD in the four-bar linkage using the relative velocity graphical methodarrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forwardFour-bar linkage mechanism, AB=40mm, BC=60mm, CD=70mm, AD=80mm, =60°, w1=10rad/s. Determine the direction and magnitude of w3 using relative motion graphical method. A B 2 3 77777 477777arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Welding: Principles and Applications (MindTap Cou...Mechanical EngineeringISBN:9781305494695Author:Larry JeffusPublisher:Cengage Learning
Welding: Principles and Applications (MindTap Cou...
Mechanical Engineering
ISBN:9781305494695
Author:Larry Jeffus
Publisher:Cengage Learning
Differences between Temporary Joining and Permanent Joining.; Author: Academic Gain Tutorials;https://www.youtube.com/watch?v=PTr8QZhgXyg;License: Standard Youtube License