Chemistry: Atoms First
3rd Edition
ISBN: 9781259638138
Author: Julia Burdge, Jason Overby Professor
Publisher: McGraw-Hill Education
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Chapter 25, Problem 25.67QP
(a)
Interpretation Introduction
Interpretation:
The reason for hydrogen peroxide stored in dark bottles and the amount of oxygen gas produced from the given amount of hydrogen peroxide has to be given.
To give: The reason for hydrogen peroxide stored in dark bottles
Decomposition of hydrogen peroxide
(b)
Interpretation Introduction
Interpretation:
The reason for hydrogen peroxide stored in dark bottles and the amount of oxygen gas produced from the given amount of hydrogen peroxide has to be given.
To calculate: The amount of oxygen gas produced from 15 g of 7.5 percent of hydrogen peroxide
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Using reaction free energy to predict equilibrium composition
Consider the following equilibrium:
N2 (g) + 3H2 (g) = 2NH3 (g) AG⁰ = -34. KJ
Now suppose a reaction vessel is filled with 8.06 atm of nitrogen (N2) and 2.58 atm of ammonia (NH3) at 106. °C. Answer the following questions about this
system:
?
rise
Under these conditions, will the pressure of N2 tend to rise or fall?
☐ x10
fall
Is it possible to reverse this tendency by adding H₂?
In other words, if you said the pressure of N2 will tend to rise, can that be
changed to a tendency to fall by adding H₂? Similarly, if you said the
pressure of N2 will tend to fall, can that be changed to a tendency to rise
by adding H₂?
If you said the tendency can be reversed in the second question, calculate
the minimum pressure of H₂ needed to reverse it.
Round your answer to 2 significant digits.
yes
no
☐
atm
☑
5
00.
18
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i need help with the following
Chapter 25 Solutions
Chemistry: Atoms First
Ch. 25 - Prob. 25.1QPCh. 25 - Prob. 25.2QPCh. 25 - Prob. 25.3QPCh. 25 - Prob. 25.4QPCh. 25 - Prob. 25.5QPCh. 25 - Prob. 25.6QPCh. 25 - Prob. 25.7QPCh. 25 - Prob. 25.8QPCh. 25 - Prob. 25.9QPCh. 25 - Prob. 25.10QP
Ch. 25 - Prob. 25.11QPCh. 25 - Prob. 25.12QPCh. 25 - Elements 17 and 20 form compounds with hydrogen....Ch. 25 - Prob. 25.14QPCh. 25 - Prob. 25.15QPCh. 25 - Prob. 25.16QPCh. 25 - Prob. 25.17QPCh. 25 - Prob. 25.18QPCh. 25 - Prob. 25.19QPCh. 25 - Prob. 25.20QPCh. 25 - Prob. 25.21QPCh. 25 - Prob. 25.22QPCh. 25 - Prob. 25.23QPCh. 25 - Prob. 25.24QPCh. 25 - Prob. 25.25QPCh. 25 - Prob. 25.26QPCh. 25 - Prob. 25.27QPCh. 25 - Prob. 25.28QPCh. 25 - Prob. 25.29QPCh. 25 - Prob. 25.30QPCh. 25 - Prob. 25.31QPCh. 25 - Prob. 25.32QPCh. 25 - Prob. 25.33QPCh. 25 - Prob. 25.34QPCh. 25 - Prob. 25.35QPCh. 25 - Prob. 25.36QPCh. 25 - Prob. 25.37QPCh. 25 - Prob. 25.38QPCh. 25 - Prob. 25.39QPCh. 25 - Prob. 25.40QPCh. 25 - Prob. 25.41QPCh. 25 - At 620 K, the vapor density of ammonium chloride...Ch. 25 - Prob. 25.43QPCh. 25 - Prob. 25.44QPCh. 25 - Prob. 25.45QPCh. 25 - Prob. 25.46QPCh. 25 - Prob. 25.47QPCh. 25 - Prob. 25.48QPCh. 25 - Prob. 25.49QPCh. 25 - Prob. 25.50QPCh. 25 - Prob. 25.51QPCh. 25 - Prob. 25.52QPCh. 25 - Prob. 25.53QPCh. 25 - Prob. 25.54QPCh. 25 - Prob. 25.55QPCh. 25 - Prob. 25.56QPCh. 25 - Prob. 25.57QPCh. 25 - Prob. 25.58QPCh. 25 - Prob. 25.59QPCh. 25 - Prob. 25.60QPCh. 25 - Prob. 25.61QPCh. 25 - Prob. 25.62QPCh. 25 - Prob. 25.63QPCh. 25 - Prob. 25.64QPCh. 25 - Prob. 25.65QPCh. 25 - Prob. 25.66QPCh. 25 - Prob. 25.67QPCh. 25 - Prob. 25.68QPCh. 25 - Prob. 25.69QPCh. 25 - Prob. 25.70QPCh. 25 - Prob. 25.71QPCh. 25 - Prob. 25.72QPCh. 25 - What are the oxidation numbers of O and F in HFO?Ch. 25 - Prob. 25.74QPCh. 25 - Prob. 25.75QPCh. 25 - Prob. 25.76QPCh. 25 - Prob. 25.77QPCh. 25 - Prob. 25.78QPCh. 25 - Prob. 25.79QPCh. 25 - Prob. 25.80QPCh. 25 - Prob. 25.81QPCh. 25 - Prob. 25.82QPCh. 25 - Prob. 25.83QPCh. 25 - Prob. 25.84QPCh. 25 - Iodine pentoxide (I2O5) is sometimes used to...Ch. 25 - Prob. 25.86QPCh. 25 - Prob. 25.87QPCh. 25 - Prob. 25.88QPCh. 25 - Prob. 25.89QPCh. 25 - Prob. 25.90QPCh. 25 - Prob. 25.91QPCh. 25 - Prob. 25.92QPCh. 25 - Prob. 25.93QPCh. 25 - Prob. 25.94QPCh. 25 - Prob. 25.95QPCh. 25 - Prob. 25.96QPCh. 25 - Prob. 25.97QPCh. 25 - Prob. 25.98QPCh. 25 - Prob. 25.99QPCh. 25 - Prob. 25.100QPCh. 25 - Prob. 25.101QPCh. 25 - Prob. 25.102QPCh. 25 - Prob. 25.103QPCh. 25 - Prob. 25.104QP
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- Using reaction free energy to predict equilibrium composition Consider the following equilibrium: 2NO(g) +Cl₂ (g) = 2NOC1 (g) AGº = -41. kJ Now suppose a reaction vessel is filled with 8.90 atm of chlorine (C12) and 5.71 atm of nitrosyl chloride (NOC1) at 1075. °C. Answer the following questions about this system: rise Under these conditions, will the pressure of NOCI tend to rise or fall? x10 fall Is it possible to reverse this tendency by adding NO? In other words, if you said the pressure of NOCI will tend to rise, can that be changed to a tendency to fall by adding NO? Similarly, if you said the pressure of NOCI will tend to fall, can that be changed to a tendency to rise by adding NO? yes no If you said the tendency can be reversed in the second question, calculate the minimum pressure of NO needed to reverse it. Round your answer to 2 significant digits. atm ☑ 18 Ararrow_forwardIdentifying the major species in weak acid or weak base equilibria The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HCN is a weak acid. acids: 0.29 mol of NaOH is added to 1.0 L of a 1.2M HCN solution. bases: ☑ other: 0.09 mol of HCl is added to acids: 1.0 L of a solution that is bases: 0.3M in both HCN and KCN. other: 0,0,... ? 00. 18 Ar 日arrow_forwardIdentifying the major species in weak acid or weak base equilibria The preparations of two aqueous solutions are described in the table below. For each solution, write the chemical formulas of the major species present at equilibrium. You can leave out water itself. Write the chemical formulas of the species that will act as acids in the 'acids' row, the formulas of the species that will act as bases in the 'bases' row, and the formulas of the species that will act as neither acids nor bases in the 'other' row. You will find it useful to keep in mind that HF is a weak acid. acids: 0.2 mol of KOH is added to 1.0 L of a 0.5 M HF solution. bases: Х other: ☐ acids: 0.10 mol of HI is added to 1.0 L of a solution that is 1.4M in both HF and NaF. bases: other: ☐ 0,0,... ด ? 18 Ararrow_forward
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