Quantitative Chemical Analysis 9e And Sapling Advanced Single Course For Analytical Chemistry (access Card)
9th Edition
ISBN: 9781319090241
Author: Daniel C. Harris, Sapling Learning
Publisher: W. H. Freeman
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Question
Chapter 25, Problem 25.38P
a)
Interpretation Introduction
Interpretation:
The high or low concentration of Acetonitrile in the next run of reversed-phase chromatography has to be given.
Concept Introduction:
Reversed-phase chromatography:
One of the most common mode of HPLC is the reversed-phase chromatography. In reversed-phase chromatography, the mobile phase is more polar and the stationery phase is nonpolar or weakly polar. The solute is more rapidly eluted from the column in reversed-phase chromatography as the mobile phase is polar. Less polar mobile phase (solvent) has a high mobile phase strength.
This method is adequate to separate mixtures of low molecular mass.
To give the concentration of Acetonitrile in reversed-phase chromatography
b)
Interpretation Introduction
Interpretation:
The high or low concentration of Hexane in the next run of normal-phase chromatography has to be given.
Concept Introduction:
Normal-phase chromatography:
Normal-phase chromatography is another method of HPLC. The stationery phase present in normal-phase chromatography is polar and the mobile phase is non-polar or weakly polar. The solute particles are soluble in polar mobile phase. This is why the mobile phase strength increases as the solvent becomes more polar.
To give the concentration of Hexane in normal-phase chromatography
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Write the answer below.
Also, in each of the drawing areas below is a copy of the molecule, with Hs shown. In each copy, one of the H atoms is colored red. Highlight in red all other H
atoms that would contribute to the same signal as the H already highlighted red.
Note for advanced students: In this question, any multiplet is counted as one signal.
Number of signals in the 'H NMR spectrum.
For the molecule in the top drawing area, highlight in red any other H atoms that will contribute to
the same signal as the H atom already highlighted red.
If no other H atoms will contribute, check the box at right.
No additional Hs to color in top
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No additional Hs to color in bottom
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In the drawing area below, draw the major products of this organic reaction:
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2. CH3Br
If there are no major products, because nothing much will happen to the reactant under these reaction conditions, check the box under the drawing area
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Chapter 25 Solutions
Quantitative Chemical Analysis 9e And Sapling Advanced Single Course For Analytical Chemistry (access Card)
Ch. 25.1 - Prob. 1TYCh. 25.3 - Prob. 2TYCh. 25.3 - Prob. 3TYCh. 25 - Prob. 25.AECh. 25 - Prob. 25.BECh. 25 - Prob. 25.CECh. 25 - Prob. 25.DECh. 25 - Prob. 25.EECh. 25 - Prob. 25.1PCh. 25 - Prob. 25.2P
Ch. 25 - Prob. 25.3PCh. 25 - Prob. 25.4PCh. 25 - Prob. 25.6PCh. 25 - Prob. 25.7PCh. 25 - Prob. 25.9PCh. 25 - Prob. 25.10PCh. 25 - Prob. 25.11PCh. 25 - Prob. 25.12PCh. 25 - Prob. 25.13PCh. 25 - Prob. 25.14PCh. 25 - Prob. 25.15PCh. 25 - Prob. 25.16PCh. 25 - Prob. 25.18PCh. 25 - Prob. 25.19PCh. 25 - Prob. 25.20PCh. 25 - Prob. 25.21PCh. 25 - Prob. 25.22PCh. 25 - Prob. 25.23PCh. 25 - Prob. 25.24PCh. 25 - Prob. 25.25PCh. 25 - Prob. 25.26PCh. 25 - Prob. 25.27PCh. 25 - Prob. 25.28PCh. 25 - Prob. 25.29PCh. 25 - Prob. 25.30PCh. 25 - Prob. 25.31PCh. 25 - Prob. 25.32PCh. 25 - Prob. 25.33PCh. 25 - Prob. 25.34PCh. 25 - Prob. 25.35PCh. 25 - Prob. 25.37PCh. 25 - Prob. 25.38PCh. 25 - Prob. 25.40PCh. 25 - Prob. 25.41PCh. 25 - Prob. 25.42PCh. 25 - Prob. 25.43PCh. 25 - Prob. 25.44P
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