Chapter 24.2, Problem 13R

To determine

To calculate: Temperature required to form ceramic B and its density.

Answer to Problem 13R

Temperature required to form ceramic B = $\underset{\_}{\text{725}°\text{C}}$ .

Density of ceramic B = $\underset{\_}{21.2{\text{ g/cm}}^3}$ .

Explanation of Solution

Given info:

Ceramic A forms when heated to $1400°\text{C}$ and has a density of $\text{5}{\text{.3 g/cm}}^3$ .

Ceramic B forms at a temperature $675°\text{C}$ cooler and is four times as dense.

Calculation:

As per question,

Ceramic A forms when heated to $1400°\text{C}$ and Ceramic B forms at a temperature $675°\text{C}$ cooler. Therefore,

Temperature required to form ceramic B = $1400°\text{C}-675°\text{C = 725}°\text{C}$

Ceramic A has a density of $\text{5}{\text{.3 g/cm}}^3$ and ceramic B is four times dense. Therefore,

Density of ceramic B = $\text{(5}\text{.3}\times {\text{4) g/cm}}^3=21.2{\text{ g/cm}}^3$

Conclusion:

Temperature required to form ceramic B = $\underset{\_}{\text{725}°\text{C}}$ .

Density of ceramic B = $\underset{\_}{21.2{\text{ g/cm}}^3}$ .