DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Textbook Question
Chapter 24, Problem 6RQ
Milling has a higher metal removal rate than planing. Why
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3. A slot of 20 mm width is to be produced using horizontal milling machine. The ks 5,000
N/mm?, cutting speed is 50 m/min, feed rate is 200 mm/min, depth of cut is 4 mm, cutter
diameter is 140 mm, and the number of teeth is 12. Calculate the machining power.
Chapter 24 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 24 - Suppose that you wanted to machine cast iron with...Ch. 24 - How is the feed per tooth related to the feed rate...Ch. 24 - Why must the number of teeth on the cutter be...Ch. 24 - Why is the question of up or down milling more...Ch. 24 - For producing flat surfaces in mass-production...Ch. 24 - Milling has a higher metal removal rate than...Ch. 24 - Which type of milling (up or down) is being done...Ch. 24 - Why does down milling dull the cutter more rapidly...Ch. 24 - What parameters do you need to specify in order to...Ch. 24 - In Figure 24.2b, the tool material is carbide....
Ch. 24 - What is the advantage of a helical-tooth cutter...Ch. 24 - What would the cutting force diagram for Fc look...Ch. 24 - Could the stub arbor-mounted face mill shown in...Ch. 24 - In a typical solid arbor milling cutter shown in...Ch. 24 - Make some sketches to show how you would you set...Ch. 24 - Make some sketches to show how you would set up a...Ch. 24 - Explain how controlled movements of the work m...Ch. 24 - Prob. 18RQCh. 24 - What is the purpose of the hole-circle plate on a...Ch. 24 - You have selected a feed per tooth and a cutting...Ch. 24 - How much time will be required for a milling...Ch. 24 - If the depth of cut is 0.35 in., what is the metal...Ch. 24 - Prob. 4PCh. 24 - Calculate the spindle rpm and table feed (ipm) for...Ch. 24 - A gray cast iron surface 6 in. wide and 18 in....Ch. 24 - Prob. 7PCh. 24 - In Figure 24.12, the feed is 0.006 in. per tooth....Ch. 24 - Suppose you want to do the job described in...Ch. 24 - The Bridgeport vertical-spindle milling machine is...Ch. 24 - The KC Machine Works, which does job shop...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Which of the below is true for conventional milling: Chips are removed behind the cutter which reduces the chance of re-cutting Chip width starts from zero and increases which causes more heat to diffuse into the workpiece and produces work hardening O Creates cleaner shear plane which causes the tool to rub less and increases tool lifearrow_forwardPlease answer correctly i will you 5 likes.arrow_forwardDetermine the total machining time for a workpiece 30mm in diameter and the required length is 145 mm. Other data: Material: 38mm dia. X 149 mm Depth of cut (turning): 4mm Depth of cut (facing): 2mm Feed : 0.05 mm/rev : 35 SMPM Cutting speedarrow_forward
- In an orthogonal cutting operation an 8 mm deep groove is to be turned on a 50 mm diameter steel bar. Spindle speed is 300 rpm and a feed rate of 0.25 mm/rev is given to the tool. Produced chips have a width of 2 mm. Calculate the material removal rate at the beginning and at the end of the cut. Can u help me please?arrow_forwardIn 3-axis milling, the table feedrate is 703.00 mm/min. Using a 10mm endmill to cut the material with a radial depth of 4.60 mm and axial depth of 4.20 mm, what is the material removal rate (Cm³ /min) in this operation? Your Answer: Answerarrow_forwardd) A face milling operation is used to machine 6.0 mm from the top surface of a rectangular piece of aluminum 300 mm long by 125 mm wide in a single pass. The cutter has four teeth (cemented carbide inserts) and is 150 mm in diameter. The cutting speed = 2.8 m/s, and chipload = 0.27 mm/tooth. Assuming that the cutter enters the workpiece from its short side and follows a path that is centered over the workpiece, determine: i) the actual machining time to make the pass across the surface and, ii) the maximum metal removal rate during cutting.arrow_forward
- For pocket operation of 2 x 3 inch surface and dept of 0.06 in using 0.5 in end mill tool. What is the time required to finished a cut when the depth of cut is 0.3 inch and the feed rate 0.05 inch/rev, spindle RPM is 60. The subject is Machine Shop Theory. Please make clear the solution and answer and understandable. Thanksarrow_forwardThe end of a large tubular workpart is to be faced on a NC vertical boring mill. The part has an outside diameter of 38.0 in and an inside diameter of 24.0 in. If the facing operation is performed at a rotational speed of 40.0 rev/min, feed of 0.015 in/rev, and depth of cut of 0.180 in, determine (a) the cutting time to complete the facing operation and the cutting speeds and metal removal rates at the beginning and end of the cut.arrow_forwardA surface of 43 mm x 246 mm will be machined by using a shaper and 7 mm deep stock will be removed from the surface. The shaper is operating at 24 strokes/minute and feed is 0.7 mm/stroke. If the maximum stroke length is 827 mm and allowable depth of cut is 0.4 mm for both of rough and finish cuts, what is the total machining time, in minutes ?arrow_forward
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