DeGarmo's Materials and Processes in Manufacturing
12th Edition
ISBN: 9781118987674
Author: J. T. Black, Ronald A. Kohser
Publisher: WILEY
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Chapter 24, Problem 5P
Calculate the spindle rpm and table feed (ipm) for a face milling machine after the speed and feed per tooth are selected. Use Figure 24.3 for reference. Work material-bronze.
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Chapter 24 Solutions
DeGarmo's Materials and Processes in Manufacturing
Ch. 24 - Suppose that you wanted to machine cast iron with...Ch. 24 - How is the feed per tooth related to the feed rate...Ch. 24 - Why must the number of teeth on the cutter be...Ch. 24 - Why is the question of up or down milling more...Ch. 24 - For producing flat surfaces in mass-production...Ch. 24 - Milling has a higher metal removal rate than...Ch. 24 - Which type of milling (up or down) is being done...Ch. 24 - Why does down milling dull the cutter more rapidly...Ch. 24 - What parameters do you need to specify in order to...Ch. 24 - In Figure 24.2b, the tool material is carbide....
Ch. 24 - What is the advantage of a helical-tooth cutter...Ch. 24 - What would the cutting force diagram for Fc look...Ch. 24 - Could the stub arbor-mounted face mill shown in...Ch. 24 - In a typical solid arbor milling cutter shown in...Ch. 24 - Make some sketches to show how you would you set...Ch. 24 - Make some sketches to show how you would set up a...Ch. 24 - Explain how controlled movements of the work m...Ch. 24 - Prob. 18RQCh. 24 - What is the purpose of the hole-circle plate on a...Ch. 24 - You have selected a feed per tooth and a cutting...Ch. 24 - How much time will be required for a milling...Ch. 24 - If the depth of cut is 0.35 in., what is the metal...Ch. 24 - Prob. 4PCh. 24 - Calculate the spindle rpm and table feed (ipm) for...Ch. 24 - A gray cast iron surface 6 in. wide and 18 in....Ch. 24 - Prob. 7PCh. 24 - In Figure 24.12, the feed is 0.006 in. per tooth....Ch. 24 - Suppose you want to do the job described in...Ch. 24 - The Bridgeport vertical-spindle milling machine is...Ch. 24 - The KC Machine Works, which does job shop...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Calculate spindle speed and feed for the two following situations: a. Use an HSS 1/2"-diameter three-flute endmill to mill 6061 aluminum 350 SFPM using a 0.0015" chip load. b. Use a carbide 3"-diameter eight-tooth shell mill to machine H13 tool steel at 200 SFPM using a 0.003" chip load.arrow_forwardsolvearrow_forwardThe end of a large tubular workpart is to be faced on a NC vertical boring mill. The part has an outside diameter of 38.0 in and an inside diameter of 24.0 in. If the facing operation is performed at a rotational speed of 40.0 rev/min, feed of 0.015 in/rev, and depth of cut of 0.180 in, determine (a) the cutting time to complete the facing operation and the cutting speeds and metal removal rates at the beginning and end of the cut.arrow_forward
- QUESTION 5 Determine the spindle speed (rpm), the feed rate (in/min) and the cutting power required for turning a 1º diameter copper rod with a depth of cut of 0.1" using a cemented carbide tool. O N=287 RPM, F-25.8 in/min, P=9.7 hp ON=2866 RPM, F=258 in/min, P=97 hp ON=1146 RPM, F-25.8 in/min, P=97 hp O N= 11460 RPM, F-340 in/min, P=130 hp ON= 1146 RPM, F-34 inimin, P= 13 hp ON= 115 RPM, F-3.4 in/min, P=1.3 hp QUESTION 6 It is required to face mill an aluminum block to size it down from 2" to 1.5" thick using a 3" diameter 2-toothed carbide cutting tool. The block is 6.0" wide and 6" long. The entire tool diameter engages the workpiece during the cut. Calculate the recommended spindle speed in revolutions per minute, feed per tooth, and cutting power required. O N=1529 RPM, f= 0.026 in/rev/tooth, P = 36 hp O N-3820 RPM, f= 26 in/revitooth, P=27 hp O N-3820 RPM, f= 0.052 in/rew/tooth, P=27 hp ON-382 RPM, F= 0.026 in/revitooth, P = 0.027 hp O N-3820 RPM, f= 0.052 in/rev/tooth, P=2.7 hp…arrow_forwardA drilling operation is performed to create a through hole on a steel plate that is 20 mm thick. Cutting speed = 0.4 m/s, and feed = 0.20 mm/rev. The 18-mm-diameter twist drill has a point angle of 120°. Determine the following once the drill reaches full diameter: a. the machining time and, b. the metal removal rate Equation used Tm TD₂L fvarrow_forwardthickness is HW3.A block of steel has a length L-600mm and a width W-450mm. The Machined 10mm, once by Peripheral Milling and once by planing Machine.Calculate :Machining time for each operation if you know the following For peripheral milling: cutting speed V =80 m/min, Feed f-0.15mm/rev, the cutter .1 diameter D =50 mm with five teeth and depth of cut d =3mm For planing: clearance on both sides c =25mm, cutting speed V =36.56 m/min, retum to .2 cutting ratio m =0.25, feed f=5 mm/stroke and depth of cut d =5 mm .Calculate Material removal rate in both processes .3 Solutionarrow_forward
- Please need within 30 min Thank you.arrow_forwardNeed accurate answer for this pleasearrow_forwardIn a slab milling operation , L_w = 200 mm table feed = 18 mm/min, diameter of cutter = 34 mm depth of cut = 2 mm. Considering approach and overtravel to be same. The milling time in min will be?arrow_forward
- Solve First one Onlyarrow_forwardA mild steel specimen of Initial diameter of 30.5 mm is turned to final diameter of 27 mm for an initial length of 153 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.4 mm/rev & Depth of cut is 0.5 mm (ii)During machining the tool's approach length is 5 mm, over run length is 2mm (iii) Time required to complete one single turning operation is 3.5 minutes (a)Find number of passes to finish the entire turning operation (b) Total time required to complete the turning operation in minutesarrow_forwardA mild steel specimen of Initial diameter of 30.5 mm is turned to final diameter of 27 mm for an initial length of 153 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.4 mm/rev & Depth of cut is 0.5 mm (ii)During machining the tool's approach length is 5 mm, over run length is 2mm (iii) Time required to complete one single turning operation is 3.5 minutes (c) Spindle speed in in rpm (= (d) Cutting speed in m/minutes(=arrow_forward
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