(a) Interpretation: The product that is formed from a Michael reaction of the given starting materials by using − OEt , EtOH is to be drawn. Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β − carbon of the other α , β − unsaturated carbonyl compound is known as Michael reaction. The α , β − unsaturated carbonyl compounds are also called as Michael acceptors.

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Answer 1

Question

Chapter 24, Problem 24.42P

Interpretation Introduction

(a)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Interpretation Introduction

(b)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

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6. Consider the following exothermic reaction below. 2Cu2+(aq) +41 (aq)2Cul(s) + 12(aq) a. If Cul is added, there will be a shift left/shift right/no shift (circle one). b. If Cu2+ is added, there will be a shift left/shift right/no shift (circle one). c. If a solution of AgNO3 is added, there will be a shift left/shift right/no shift (circle one). d. If the solvent hexane (C6H14) is added, there will be a shift left/shift right/no shift (circle one). Hint: one of the reaction species is more soluble in hexane than in water. e. If the reaction is cooled, there will be a shift left/shift right/no shift (circle one). f. Which of the changes above will change the equilibrium constant, K?

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Answer 2

Question

Chapter 24, Problem 24.42P

Interpretation Introduction

(a)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Interpretation Introduction

(b)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

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Answer 3

Question

Chapter 24, Problem 24.42P

Interpretation Introduction

(a)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Interpretation Introduction

(b)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

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Answer 4

Question

Chapter 24, Problem 24.42P

Interpretation Introduction

(a)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Interpretation Introduction

(b)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

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Answer 5

Chapter 24, Problem 24.42P

Interpretation Introduction

(a)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Interpretation Introduction

(b)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Answer 6

Chapter 24, Problem 24.42P

Interpretation Introduction

(a)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Answer 7

Chapter 24, Problem 24.42P

Interpretation Introduction

(a)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Answer 8

Interpretation Introduction

(b)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Answer 9

Interpretation Introduction

(b)

Interpretation: The product that is formed from a Michael reaction of the given starting materials by using −OEt, EtOH is to be drawn.

Concept introduction: The reaction in which an enolate ion of one carbonyl compound undergoes conjugate addition reaction with the β−carbon of the other α,β−unsaturated carbonyl compound is known as Michael reaction. The α,β−unsaturated carbonyl compounds are also called as Michael acceptors.

Answer 10

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Answer 11

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Answer 13

Ch. 24 - Prob. 24.1P Ch. 24 - Prob. 24.2P Ch. 24 - Problem 24.3 What unsaturated carbonyl compound is...Ch. 24 - Prob. 24.4P Ch. 24 - Prob. 24.5P Ch. 24 - Prob. 24.6P Ch. 24 - Problem 24.7 Draw the products formed in each...Ch. 24 - Problem 24.8 Draw the products formed in the...Ch. 24 - Prob. 24.9P Ch. 24 - Prob. 24.10P

Solution Summary: The author explains that the product that is formed from a Michael reaction of the given starting materials by using -OEt is shown.

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Chapter 24 Solutions