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Chapter 23.SE, Problem 62AP
Interpretation Introduction

a)

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  1

Interpretation:

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are to be given.

Concept introduction:

Michael reaction involves the conjugate addition of a stable enolate ion derived from a β-ketoesters or β-diketones or β-ketonitriles or malonic esters (donors) to an unhindered α,β-unsaturated ketones or aldehydes or esters or thioesters or nitriles or amides or nitro compounds (acceptors). The enolate ion from the donor attacks the double bond in acceptor. A new bond is formed between the α-carbon of the donor and the β-carbon of the unsaturated ester.

To give:

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown.

Expert Solution
Check Mark

Answer to Problem 62AP

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  2

Explanation of Solution

An analysis of the structure of the compound indicates that it is formed by the reaction between the ethylacetoacetate (nucleophilic donor) and phenyl vinyl ketone (electrophilic acceptor).

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  3

Conclusion

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  4

Interpretation Introduction

b)

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  5

Interpretation:

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are to be given.

Concept introduction:

Michael reaction involves the conjugate addition of a stable enolate ion derived from a β-ketoesters or β-diketones or β-ketonitriles or malonic esters (donors) to an unhindered α,β-unsaturated ketones or aldehydes or esters or thioesters or nitriles or amides or nitro compounds (acceptors). The enolate ion from the donor attacks the double bond in acceptor. A new bond is formed between the α-carbon of the donor and the β-carbon of the unsaturated ester.

To give:

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown.

Expert Solution
Check Mark

Answer to Problem 62AP

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  6

Explanation of Solution

An analysis of the structure of the compound indicates that it is formed by the reaction between the ethylacetoacetate (nucleophilic donor) and methyl vinyl ketone (electrophilic acceptor).

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  7

Conclusion

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  8

Interpretation Introduction

c)

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  9

Interpretation:

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are to be given.

Concept introduction:

Michael reaction involves the conjugate addition of a stable enolate ion derived from a β-ketoesters or β-diketones or β-ketonitriles or malonic esters (donors) to an unhindered α,β-unsaturated ketones or aldehydes or esters or thioesters or nitriles or amides or nitro compounds (acceptors). The enolate ion from the donor attacks the double bond in acceptor. A new bond is formed between the α-carbon of the donor and the β-carbon of the unsaturated ester.

To give:

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown.

Expert Solution
Check Mark

Answer to Problem 62AP

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  10

Explanation of Solution

An analysis of the structure of the compound indicates that it is formed by the reaction between the ethylacetoacetate (nucleophilic donor) and vinyl nitrile (electrophilic acceptor).

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  11

Conclusion

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  12

Interpretation Introduction

d)

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  13

Interpretation:

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are to be given.

Concept introduction:

Michael reaction involves the conjugate addition of a stable enolate ion derived from a β-ketoesters or β-diketones or β-ketonitriles or malonic esters (donors) to an unhindered α,β-unsaturated ketones or aldehydes or esters or thioesters or nitriles or amides or nitro compounds (acceptors). The enolate ion from the donor attacks the double bond in acceptor. A new bond is formed between the α-carbon of the donor and the β-carbon of the unsaturated ester.

To give:

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown.

Expert Solution
Check Mark

Answer to Problem 62AP

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  14

Explanation of Solution

An analysis of the structure of the compound indicates that it is formed by the reaction between nitro ethane (nucleophilic donor) and ethylacrylate (electrophilic acceptor).

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  15

Conclusion

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  16

Interpretation Introduction

e)

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  17

Interpretation:

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound are to be given.

Concept introduction:

Michael reaction involves the conjugate addition of a stable enolate ion derived from a β-ketoesters or β-diketones or β-ketonitriles or malonic esters (donors) to an unhindered α,β-unsaturated ketones or aldehydes or esters or thioesters or nitriles or amides or nitro compounds (acceptors). The enolate ion from the donor attacks the double bond in acceptor. A new bond is formed between the α-carbon of the donor and the β-carbon of the unsaturated ester.

To give:

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown.

Expert Solution
Check Mark

Answer to Problem 62AP

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  18

Explanation of Solution

An analysis of the structure of the compound indicates that it is formed by the reaction between the ethylsuccinate (nucleophilic donor) and nitro ethene (electrophilic acceptor).

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  19

Conclusion

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  20

Interpretation Introduction

f)

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  21

Interpretation:

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are to be given.

Concept introduction:

Michael reaction involves the conjugate addition of a stable enolate ion derived from a β-ketoesters or β-diketones or β-ketonitriles or malonic esters (donors) to an unhindered α,β-unsaturated ketones or aldehydes or esters or thioesters or nitriles or amides or nitro compounds (acceptors). The enolate ion from the donor attacks the double bond in acceptor. A new bond is formed between the α-carbon of the donor and the β-carbon of the unsaturated ester.

To give:

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown.

Expert Solution
Check Mark

Answer to Problem 62AP

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  22

Explanation of Solution

An analysis of the structure of the compound indicates that it is formed by the reaction between nitro methane (nucleophilic donor) and 2-cyclopentenone (electrophilic acceptor).

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  23

Conclusion

The nucleophilic donor and electrophilic acceptor that react in a Michael reaction to yield the compound shown are

Student Value Bundle: Organic Chemistry, + OWLv2 with Student Solutions Manual eBook, 4 terms (24 months) Printed Access Card (NEW!!), Chapter 23.SE, Problem 62AP , additional homework tip  24

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Chapter 23 Solutions

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Ch. 23.7 - Show the products you would expect to obtain by...Ch. 23.7 - Prob. 12PCh. 23.8 - What product would you expect from the following...Ch. 23.9 - What product would you expect From the following...Ch. 23.9 - Prob. 15PCh. 23.10 - Prob. 16PCh. 23.10 - Prob. 17PCh. 23.10 - Prob. 18PCh. 23.11 - Prob. 19PCh. 23.11 - Show how you might use an enamine reaction to...Ch. 23.12 - Prob. 21PCh. 23.12 - How would you prepare the following compound using...Ch. 23.SE - Prob. 23VCCh. 23.SE - Prob. 24VCCh. 23.SE - Prob. 25VCCh. 23.SE - The following molecule was formed by a Robinson...Ch. 23.SE - Prob. 27MPCh. 23.SE - Prob. 28MPCh. 23.SE - Predict the product(s) and provide the mechanism...Ch. 23.SE - Predict the product(s) and provide the mechanism...Ch. 23.SE - Predict the product(s) and provide the mechanism...Ch. 23.SE - Knoevenagel condensation is a reaction involving...Ch. 23.SE - Azlactones are important starting materials used...Ch. 23.SE - Prob. 34MPCh. 23.SE - Isoleucine, another of the twenty amino acids...Ch. 23.SE - The first step in the citric acid cycle of food...Ch. 23.SE - Prob. 37MPCh. 23.SE - The Knoevenagel reaction is a carbonyl...Ch. 23.SE - The Darzens reaction invoIves a two-step,...Ch. 23.SE - The following reaction involves a hydrolysis...Ch. 23.SE - Prob. 41MPCh. 23.SE - Prob. 42MPCh. 23.SE - Prob. 43MPCh. 23.SE - Propose a mechanism for the following...Ch. 23.SE - Prob. 45MPCh. 23.SE - Prob. 46MPCh. 23.SE - Prob. 47MPCh. 23.SE - Prob. 48APCh. 23.SE - Prob. 49APCh. 23.SE - Prob. 50APCh. 23.SE - Prob. 51APCh. 23.SE - Prob. 52APCh. 23.SE - Prob. 53APCh. 23.SE - Prob. 54APCh. 23.SE - Prob. 55APCh. 23.SE - Prob. 56APCh. 23.SE - Prob. 57APCh. 23.SE - Prob. 58APCh. 23.SE - In the mixed Claisen reaction of cyclopentanone...Ch. 23.SE - Ethyl dimethylacetoacetate reacts instantly at...Ch. 23.SE - Prob. 61APCh. 23.SE - Prob. 62APCh. 23.SE - The so-called Wieland-Miescher ketone is a...Ch. 23.SE - Prob. 64APCh. 23.SE - Prob. 65APCh. 23.SE - Prob. 66APCh. 23.SE - What condensation products would you expect to...Ch. 23.SE - The following reactions are unlikely to provide...Ch. 23.SE - Fill in the missing reagents a-h in the following...Ch. 23.SE - Prob. 70APCh. 23.SE - Prob. 71APCh. 23.SE - Prob. 72APCh. 23.SE - Prob. 73AP
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