The lens-maker’s equation for a lens with index n1 immersedin a medium with index n2 takes the formA thin diverging glass (index = 1.50) lens with R1 = –3.00 m and R2 = –6.00 m is surrounded by air. An arrow is placed 10.0 m to the left of the lens. (a) Determine the position of the image. Repeat part (a) with the arrow and lens immersed in (b) water (index = 1.33) (c) a medium with an index of refraction of 2.00. (d) How can a lens that is diverging in air be changed into a converging lens?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
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The lens-maker’s equation for a lens with index n1 immersed

in a medium with index n2 takes the form

 width=

A thin diverging glass (index = 1.50) lens with R1 = –3.00 m and R2 = –6.00 m is surrounded by air. An arrow is placed 10.0 m to the left of the lens. (a) Determine the position of the image. Repeat part (a) with the arrow and lens immersed in (b) water (index = 1.33) (c) a medium with an index of refraction of 2.00. (d) How can a lens that is diverging in air be changed into a converging lens?

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