A concave spherical mirror has a radius of curvature whose absolute value is 17.2 cm . An object is placed at a distance 6.95 cm in front of the mirror. a) Calculate the image distance of the object, including appropriate sign (give answer in cm). B) Calculate the magnification of the image, including appropriate sign
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- The figure shows an object and its image formed by a thin lens. Assume that d1 = 0.595 m, d2 = 0.784 m, and h = 7.50E-2 m. What is the image height (in m; answer sign and magnitude)? give answer in 3 sig figs and scientific notationA concave mirror is placed 10 cm in front of an object. The image measures 6 cm, and the image-mirror distance is 40 cm. Solve completely and find: a) radius of curvature in meters or cm and focal length in meters or cm b) magnification and the size of the object in cm c) Say if the image is real or virtual, if the image is reduced, the same size or enlarged and if the image is erect or invertedAll problems involve a concave (converging) mirror that has a radius of curvature of 18.0 m.For problems 1-4, an object of height 12.0 cm is placed 15.00 m in front of the mirror. Calculate the image distance, the image height, and the magnification(not necessarily in that order). 1) Calculate di. 2) Calculate hi. 3) Calculate the magnification m. 4) Where is the image formed? A) on the object side of the optic B) on the side of the optic opposite the object C) there is no image formed
- A spherical concave lens has a focal length of 50 cm, and an object is placed 20 cm from the lens. Draw a ray diagram. (Submit a file with a maximum size of 1 MB.) Choose File No file chosen Estimate the image distance. cmHow far behind a 28.6 cm magnifying glass would you put a fingerprint to get an upright image 2.259 times as large? Answer in cm. Would this be a real or virtual image (answer to yourself).An object is placed a distance do in front of a concave mirror with a radius of curvature r = 6 cm. The image formed has a magnification of M = 2.5. a) Write an expression for the object's distance, do. b) Numerically, what is the distance in cm?
- A convex mirror has a focal length of magnitude 6.08 cm. (a) If the image is virtual, what is the object location for which the magnitude of the image distance is one third the magnitude of the object distance? (Enter distance in cm from the front of the mirror. If the image is real, enter NONE.) cm (b) Find the magnification of the image. State whether it is upright or inverted. O upright invertedEither all parts or none.... Vll upvoteHomework 12 Problem 4: A shopper standing 2.75 m from a convex security mirror sees his image with a magnification of 0.23. Part (a) What is his image distance in meters, measured from the surface of the mirror, given that the object distance is positive? di = ______ Part (b) What is the focal length of the mirror, in meters? f = ______ Part (c) What is its radius of curvature in meters? R = ______
- A virtual upright image is .25 times the size of the object. a) If the object is 20.0 cm in front of the mirror what is the object distance. b) What is the focal length of the mirror and is it concave, convex, or plane? Show the algebraic form of any equation(s) applied. Report answers to with the correct units and number of significant figures.Problem 6: You are looking for a mirror that will enable you to see a 3.4-times magnified virtual image of an object that is placed 4.2 cm from the mirror’s vertex. A concave mirror will be used Part (b) What should the mirror’s radius of curvature be, in centimeters?An object is 30.0 from a spherical mirror, 1 magnification is. The image produced is inverted. What is along the central axis. The absolute value of lateral 2 the focal length of the mirror?