1) What is f, the focal length of the mirror? If the mirror is concave f is positive. If the mirror is convex, f is negative. cm Submit 2) What is y2, the y-coordinate of the image of the tip of the arrow? cm Submit + cm Submit + 3) The object arrow is now moved such that image distance doubles, i.e., Ximage, new = -177 cm. What is Yimage, new, new y-coordinate of the image of the tip of the arrow? the
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- A spherical mirror is to be used to form an image that is 4.75 times the size of the object, on a screen located 5.05.0m behind the object (specifically, the arrangement looks like [image]----- [object] ----- [mirror]). Part A) What kind of mirror should be used? A. Flat mirror B. Either a concave or a convex mirror would work C. Convex mirror D. Any kind of mirror would work E. Concave mirror F. It is impossible to achieve this magnification with any mirror Part B) Draw a ray diagram illustrating how the enlarged image is formed from the object. You do not need to turn in this ray diagram, but it will help answer the remaining parts of this question. Which of the following describes where the object will be placed relative to the mirror? A. Between the focal length and the center of curvature B.Further than the center of curvature C. Closer than the focal length D. The object can be placed anywhere relative to the mirror…A cosmetic mirro is designed to magnifiy your face by a factor of 1.53 when your face is 16cm in front of it. a) what type of mirror is it? concave, plane, or convex b) describe the image formed 1. virtual or real 2. upright or inverted 3. reduced or magnified c) calculate the radius of the curvature of the mirror (in cm)The mirror equation relates the object distance, d0, the image distance, di, and the focal length, f, of a mirror as1 / d0 + 1 / di = 1 / fWhile in other topics, distance and length are strictly non-negative, in optics we introduce the following sign conventions: Object distance is positive for a real object and negative for a virtual object. Image distance is positive for a real image and negative for a virtual image. Focal length is positive for a converging mirror and negative for a diverging mirror (a) Select the best choice to complete this statement. A real object placed in front of a converging mirror creates a real image under all circumstances. under no circumstances. when the object is between the focal point and the mirror. when the object is farther than the focal length from the mirror. (b) Select the best choice to complete this statement. A real object placed in front of a diverging mirror creates a virtual image under all circumstances. under no circumstances.…
- 3. A concave makeup mirror is designed to produce a virtual image that is one and a half times the size of the object when the distance between the object and the mirror is 17.0 cm. What is the focal length of the mirror? cm4. An object placed 15.0 cm in front of a convex mirror produces an image that is three-fourths the size of the object. What is the focal length of the mirror?(include the proper algebraic sign to reflect the nature of the mirror) cmAn orthogonal projection of an object in a 2D drawing of an object as it would appear with all its feature projected perpendicular to a viewing ...True? A. yes B.No
- Work with your neighbors to fill in the table below. If a number has (+) written in front of it, then you must determine if the number should be positive or negative. mirror type concave focal radius of length curv. (+)20 cm +20 cm -40 cm object image magnifi- distance distance cation +10 cm +10 cm +30 cm -10 cm 1.0 real or virtual? inverted. or not?ONLY ANSWER IN SCIENTIFIC NOATION USING E IF YOU CAN NOT DO BOTH DO NOT RESPOND THANKSThe diagram below shows a ray of light striking a mirror AB. The mirror AB and the mirror CD are at right angles to each other. QN is the normal to the mirror AB. a) What is the angle of incidence of the ray PQ on the mirror AB? b) Continue the ray on the diagram to show the path it takes after reflection at both mirrors, indicating the values of all angles of incidence and reflection.
- if an object with a height of 3 cm is imaged by an optical system with a magnification of -4, the image height will be? a)-12 cm b)+12 cmAssuming the orientation of the object is upright, if the magnification of a mirror or lens is negative, it means that A) the image must be smaller than the object. B) the image must be inverted and smaller than the object. C) the image must be inverted. D) the object must be farther from the mirror (or lens) than the image. E) the image must be farther from the mirror (or lens) than the object.4. An object placed 20.0 cm in front of a convex mirror produces an image that is one-fourth the size of the object. What is the focal length of the mirror?(include the proper algebraic sign to reflect the nature of the mirror) cm