The figure below shows an object placed a distance do1 from one of two converging lenses separated by s = 1.00 m. The first lens has focal length f₁ = 21.0 cm, and the second lens has focal length f₂ = 43.0 cm. An image is formed by light passing through both lenses at a distance d;2 = 16.0 cm to the left of the second lens. (Include the sign of the value in your answers.) Object (a) What is the value of doi that will result in this image position? cm Final image position (b) Is the final image formed by the two lenses real or virtual? O real O virtual (c) What is the magnification of the final image? (d) Is the final image upright or inverted? O upright inverted
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Q: The figure below shows an object placed a distance do1 from one of two converging lenses separated…
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Q: The figure below shows an object placed a distance do1 from one of two converging lenses separated…
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- In order to heighten your enjoyment of your 29 carat blue diamond, you view it through a lens held close to your right eye at an angular magnification of 5.1. The distance of your right eye's near point is 25 cm. What is the focal length f of the lens in centimeters? f = ?cmCan you help me calculate the height. I kept getting it wrong.Two lenses are placed along an optical rail. One is a converging lens, with a focal length of f1 = 30.3 cm. The second lens, a diverging lens with a focal length of f2 = −20.0 cm, is placed d = 110 cm to the right of the converging lens. An object ho = 2.02 cm high is placed p1 = 40.5 cm to the left of the converging lens. (a) Determine the position of the final image. (Enter the position in cm relative to the diverging lens.) magnitude ? cm direction right or left? of the diverging lens (b) Determine the magnification of the final image. (Indicate the orientation with the sign of your answer.) Hint* The total magnification is the product of each individual magnification. (c) Is the image upright or inverted? (d) Repeat parts (a) through (c) for the case in which the second lens is a converging lens having a focal length of 20.0 cm. (Enter the position in cm relative to the second lens. Indicate the orientation of the magnification with the sign of your…
- = A leaf of length his positioned d below. Leaf d 70.3 cm in front of a converging lens with a focal length of 34.0 cm. An observer views the image of the leaf from a position 1.26 m behind the lens, as shown in the figure 1.26 m (a) What is the magnitude of the lateral magnification (the ratio of image size to the object size) produced by the lens? (b) What angular magnification is achieved by viewing the image of the leaf rather than viewing the leaf directly?An object is placed a distance of 8.50f from a converging lens, where f is the lens's focal length. (Include the sign of the value in your answers.) (a) What is the location of the image formed by the lens? d; = f = (b) Is the image real or virtual? real virtual (c) What is the magnification of the image? (d) Is the image upright or inverted? upright invertedTwo converging lenses, each of focal length 14.9 cm, are placed 39.6 cm apart, and an object is placed 30.0 cm in front of the first lens. Where is the final image formed? The image is located cm ---Location--- in front of the first lens. in front of the second lens. behind the second lens. What is the magnification of the system? M = ✕
- Compute the focal length of a diverging thin lens made of flint glass, whose refractive index is 1.66 and is immersed in air having refractive index 1. The radii of the spherical surfaces of the lens are 10 cm and 20 cm. Select one: O -30 cm O O -10 cm 30 cm 10 cmAn object with a height of -0.040 m points below the principal axis (it is inverted) and is 0.140 m in front of a diverging lens. The focal length of the lens is -0.25 m. (Include the sign of the value in your answers.) (a) What is the magnification? (b) What is the image height? m (c) What is the image distance? mThe distance between the eyepiece and the objective lens in a certain compound microscope is 10.4 cm. The focal length of the objective is 0.430 cm, and that of the eyepiece is 1.40 cm. Find the overall magnification of the microscope. (The near point of the eye is 25 cm. Assume that the object is placed at the focal point of the objective lens, and one places the eyepiece at the near point of the eye.)
- A system of two lenses forms an image of an arrow at x = x3 = 57.4 cm. The first lens is a diverging lens located at x = 0 and has a focal length of magnitude f₁ = 11.5 cm. The second lens is located at x = x₂ = 25.4 cm and has an unknown focal length. The tip of the object arrow is located at (x,y) = (xo, Yo) = (-36 cm, 20.6 cm). (x,y) 1) What is x₁, the x-coordinate of image of the arrow formed by the first lens? cm Submit 2) What is y₁, the y-coordinate of the image of the tip of the arrow formed by the first lens? cm Submit X₂ Real and Inverted Real and Upright Virtual and Inverted Virtual and Upright cm Submit (+) 3) What is f2, the focal length of the second lens. If the lens is a converging lens, f2 is positive. If the lens is a diverging lens, f2 is negative. cm Submit + 4) What is y3, the y-coordinate of the image of the tip of the arrow formed by the two lens system? (+ 5) The positions of the two lenses are now interchnaged (i.e., the second lens is moved to x = 0 and the…A nearsighted person has a far point of 25.3cm and is prescribed contact lenses to correct her vision. What lens strength (a.k.a., lens power), in Diopters, should be prescribed? Give your answer using the usual convention of positive values for converging lenses and negative values for diverging lenses.