A 2.0 cm tall object is 30 cm to the left of a lens with a focal length of 10 cm. A second lens with a focal length of -5 cm is 30 cm to the right of the first lens. Find the location, and size, of the final image relative to the original object, and the character of the final image. Draw (two) ray diagrams to verify the result.
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A 2.0 cm tall object is 30 cm to the left of a lens with a focal length of 10 cm. A second
lens with a focal length of -5 cm is 30 cm to the right of the first lens. Find the location,
and size, of the final image relative to the original object, and the character of the final
image. Draw (two) ray diagrams to verify the result.
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- In order to read his book, Stephen uses a pair of reading glasses. When he holds the book at a distance of 22.7 cm from his eyes, the glasses form an upright image a distance of 49.9 cm from his eyes. The distance between the glasses and Stephen's eyes is negligible. What is the magnification of the lens? What is the focl length of the lens? Which of the following statements about the image and the lens is correct? Check All That Apply: The lens is converging. The lens is converging. The image is virtual. The image is virtual. The image is real. The image is real. The lens is divergingIn the figure below, the converging lens' focal length is 13.5 cm, d = 11.7 cm, and the diverging lens' focal length is -14. 1.4 cm tall object is 7.8 cm to the left of the converging lens. d (a) Where is the image formed by the converging lens, measured from that lens (using negative for a virtual image)? cm (b) How tall is the image formed by the converging lens (using negative for an inverted image)? cm (c) Where is the image formed by the diverging lens, measured from that lens (using negative for a virtual image)? cm (d) How tall is the image formed by the diverging lens (using negative for an inverted image)? cmIn a darkened room, a burning candle is placed 1.63 m from white wall. A lens is placed between candle and wall at a location that causes a larger, inverted image to form on the wall. When the lens is moved 86.6 cm toward the wall, another image of the candle is formed. K 1.63 m How far apart are the two object distances that produce these images? Answer in units of m. Find the focal length of the lens. Answer in units of m.
- A diverging lens has a front surface with a radius of |R,| = 10 cm (c.o.c. in front of lens), and a back surface with a radius of R = 15 cm (c.o.c. behind lens). What is the focal length of this lens? The index of refraction of the glass is n,= 1.50. 19.Two lenses, one converging of focal length 10.0 cm and one diverging of 5.0 cm, are placed 30.0cm apart. An object is placed 20.0 cm in front of the converging lens. Determine the location and magnification of the final image with respect to the original object.a) An object is placed 40.0cm in front of a diverging lens with a focal length of 19.2 cm. Please provide your answers in units of cm if necessary. Find the image distance. I answered this part and I got -13 as an answer. But i can't solve this second part: b) Suppose the object is brought to a distance of 11.7 cm in front of the lens. Where is the image now with respect to its previous location? (Note: Ensure the sign convention you use is consistent by treating all image distances on the object side of the lens as negative.) c)How has the height of the image changed if the object is 80.7 cm tall? plz help me answer it. thanks
- When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.20 cm-tall object is 60.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of The eye's lens. Part A Find the location and height of the image (call it I₁) formed by the lens with a focal length of 40.0 cm. Enter your answers in centimeters separated by a comma. s₁, y = 120,2.40 cm Submit Correct Set Up: Apply Solve: Lens 1: m₁ = Previous Answers Part B $1 f₁ $1-f₁ $₂,|y₂| = 1 S s' 1 S +1/1 = = gives (60.0 cm) (40.0 cm) 60.0 cm-40.0 cm to each lens. m₁ 120 cm 60.0 cm = = -2.00 = Y'₁ Y1 120 cm and m2 $1…- 25 cm. An object of height 2.8 cm is placed at 28 cm in front of a diverging lens of focal length, ƒ = Behind the diverging lens, there is a converging lens of focal length, f = 25 cm. The distance between the lenses is 3 cm. In the next few steps, you will find the location and size of the final image. Hint a. Where is the intermediate image formed by the first diverging lens? Image distance from first lens is cm. (Use the sign to indicate which side the image is on; positive sign di1 = means image is on the side of outgoing rays, and negative sign means image is on the side opposite to the outgoing rays.) b. Where is the final image formed by the second converging lens? Image distance from second lens is cm. (Use the sign to indicate which side the image is on.) d₁2 = c. How large is the intermediate image formed by the first diverging lens? Intermediate image height is cm. (Use the sign to indicate whether the image is upright (positive) or hil = inverted (negative).) = d. How…A 15.0 cm tall object is 75.0 cm to the left of a diverging lens (with focal length of magnitude 40.0 cm). A second diverging lens (with a focal length of magnitude 100.0 cm) is 57.2 cm to the right of the first lens. The object and both lenses are on the same optic axis. What is the height of the final image that is produced by light passing through both lenses?
- A convex lens of focal length 22.2 cm has an object located on its principal axis, 50.8 cm from the vertical axis of the lens. What is the height of the object (in cm) if the height of the image produced is 1.2 cm? Your answer must have at least 4 decimal places and be within 1% of the correct value. Note: You are required to insert a negative or positive number ONLY in the space provided.A lens forms an image of an object. The object is 16.0 cm from the lens. The image is 12.0 cm from the lens on the same side as the object. (a) What is the focal length of the lens? Is the lens converging or diverging? (b) If the object is 8.50 mm tall, how tall is the image? Is it erect or inverted? (c) Draw a principal-ray diagram.A camera is supplied with two interchangeable lenses, whose focal lengths are 25.0 and 110.0 mm. A woman whose height is 1.879m stands 8.60 m in front of the camera. What is the height (including sign) of her image on the film, as produced by each of the following.