A 5 cm high object is 12.0 cm in front of a system of two lenses, with f1 = 10.0 cm and f2 = -15.0 cm. The lenses are separated by d = 20.0 cm. (a) How far is the final image FROM THE CONVEX LENS and (b) on which side is it formed and (c) what is the size of the final image?
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A 5 cm high object is 12.0 cm in front of a system of two lenses, with f1 = 10.0 cm and f2 = -15.0 cm. The lenses are separated by d = 20.0 cm. (a) How far is the final image FROM THE CONVEX LENS and (b) on which side is it formed and (c) what is the size of the final image?
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- A 1.00-cm-high object is placed 4.30 cm to the left of a converging lens of focal length 8.45 cm. A diverging lens of focal length -16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position 188.8 height 26.048 X cm in front of the second lens X cmA transparent photographic slide is placed in front of a converging lens with a focal length of 2.20 cm. An image of the slide is formed 14.5 cm from the slide. (a) How far is the lens from the slide if the image is real? (b) How far is the lens from the slide if the image is virtual? Step 1 (a) The real image case is shown in the ray diagram. or Object 1 Figure 1 + P 14.5 cm P Notice that here p + q = 14.5 cm, or q = 14.5 cm - p. The thin-lens equation, with focal length f = 2.20 cm, gives 1 - p² (14.5 cm)p+ p+q = F Description Image | cm² = 0. Using the quadratic formula to solve the above equation gives two solutions. The smaller solution is p= cm and the larger solution is p = cm cm. Both are valid solutions for the real image case.A convex mirror has a focal length of -21 cm. Find the magnification produced by the mirror when the object distance is (a)12 cm and (b)22 cm. (a) m₁ = (b) m₂ = < < i M. Object Virtual image < <
- A thin lens is comprised of two spherical surfaces with radii of curvatures of 32.4 cm for the front side and -26.9 cm for the back side. The material of which the lens is compose has an index of refraction of 1.49. What is the magnification of the image formed by an object placed 43.7cm from the lens?A concave cosmetic mirror has a focal length of 26 cmcm . A 3.0 cmcm -long mascara brush is held upright 13 cmcm from the mirror. Use ray tracing to determine the location of its image in cm. Use ray tracing to determine the height of its image in cm. Is the image upright or inverted? Real or virtual?An object of height 9.00 cm is placed 26.0 cm to the left of a converging lens with a focal length of 10.5 cm. Determine the image location in cm, the magnification, and the image height in cm. HINT (a) the image location in cm cm (b) the magnification (c) the image height in cm cm (d) Is the image real or virtual? real virtual (e) Is the image upright or inverted? upright inverted
- A contact lens is made of plastic with an index of refraction of 1.60. The lens has an outer radius of curvature of +1.91 cm and an inner radius of curvature of +2.49 cm. What is the focal length of the lens? cm Need Help? Watch It Read ItThe figure shows an object and its image formed by a thin lens. Assume that d1 = 0.919 m, d2 = 0.861 m, and h = 7.50E-2 m. What is the image height (in m; answer sign and magnitude)?A system of two lenses forms an image of an arrow at x = x3 = 57.4 cm. The first lens is a diverging lens located at x = 0 and has a focal length of magnitude f₁ = 11.5 cm. The second lens is located at x = x₂ = 25.4 cm and has an unknown focal length. The tip of the object arrow is located at (x,y) = (xo, Yo) = (-36 cm, 20.6 cm). (x,y) 1) What is x₁, the x-coordinate of image of the arrow formed by the first lens? cm Submit 2) What is y₁, the y-coordinate of the image of the tip of the arrow formed by the first lens? cm Submit X₂ Real and Inverted Real and Upright Virtual and Inverted Virtual and Upright cm Submit (+) 3) What is f2, the focal length of the second lens. If the lens is a converging lens, f2 is positive. If the lens is a diverging lens, f2 is negative. cm Submit + 4) What is y3, the y-coordinate of the image of the tip of the arrow formed by the two lens system? (+ 5) The positions of the two lenses are now interchnaged (i.e., the second lens is moved to x = 0 and the…