When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.20 cm-tall object is 60.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of The eye's lens. Part A Find the location and height of the image (call it I₁) formed by the lens with a focal length of 40.0 cm. Enter your answers in centimeters separated by a comma. 120,2.40 cm Submit ✓ Correct Set Up: Apply+= Previous Answers Solve: Lens 1: ¹+¹= +++ = 8₁ Part B 81-/1 m₁ == 8/2, 3/₂= 81 = =-120 cm= -2.00 60.0 cm v=my (-2.00) (1.20 cm) = -2.40 cm. The image I₁ is 120 cm to the right of lens 1, 2.40 cm tall and inverted. = V/₁ to each lens. m₁ = and m₂ = 3/₁ gives (60.0 cm) (40.0 cm) 60.0 cm-40.0 cm = 120 cm I₁ is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination Enter your answers in centimeters separated by a comma. [ΕΙ ΑΣΦΑ 3 BwWC V/₂ 1) ? cm lenses.

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When two lenses are used in combination, the first one forms an image that then
serves as the object for the second lens. The magnification of the combination is the
ratio of the height of the final image to the height of the object. A 1.20 cm-tall object
is 60.0 cm to the left of a converging lens of focal length 40.0 cm. A second
converging lens, this one having a focal length of 60.0 cm, is located 300 cm to the
right of the first lens along the same optic axis.
For related problem-solving tips and strategies, you may want to view a Video Tutor
Solution of The eye's lens.
Part A
Find the location and height of the image (call it I₁) formed by the lens with a focal length of 40.0 cm.
Enter your answers in centimeters separated by a comma.
s₁, y = 120,2.40 cm
Submit
Correct
Set Up: Apply
Solve: Lens 1:
m₁ =
Previous Answers
Part B
$1 f₁
$1-f₁
$₂,|y₂| =
1
S s'
1
S
+1/1
=
=
gives
(60.0 cm) (40.0 cm)
60.0 cm-40.0 cm
to each lens. m₁
120 cm
60.0 cm
=
= -2.00
=
Y'₁
Y1
120 cm
and m2
$1
y₁m₁y₁ = (-2.00) (1.20 cm) = -2.40 cm. The image I₁ is 120 cm to the right of lens 1, 2.40 cm tall and inverted.
=
I₁ is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses.
Enter your answers in centimeters separated by a comma.
VE ΑΣΦ
3/₂2
Y2
Y2
?
cm
Transcribed Image Text:When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.20 cm-tall object is 60.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of The eye's lens. Part A Find the location and height of the image (call it I₁) formed by the lens with a focal length of 40.0 cm. Enter your answers in centimeters separated by a comma. s₁, y = 120,2.40 cm Submit Correct Set Up: Apply Solve: Lens 1: m₁ = Previous Answers Part B $1 f₁ $1-f₁ $₂,|y₂| = 1 S s' 1 S +1/1 = = gives (60.0 cm) (40.0 cm) 60.0 cm-40.0 cm to each lens. m₁ 120 cm 60.0 cm = = -2.00 = Y'₁ Y1 120 cm and m2 $1 y₁m₁y₁ = (-2.00) (1.20 cm) = -2.40 cm. The image I₁ is 120 cm to the right of lens 1, 2.40 cm tall and inverted. = I₁ is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses. Enter your answers in centimeters separated by a comma. VE ΑΣΦ 3/₂2 Y2 Y2 ? cm
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