Hanhyun and Gwangwoo are experimenting with lenses. They take a double convex lens with radii R1-9.00 cm and R2 = 11.0 cm. If the lens has a focal length of 5 cm in air, what is its index of refraction in cm? What is its focal length in cm in water which has an index of refraction of 1.33?

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Chapter1: Units, Trigonometry. And Vectors
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**Experimenting with Lenses: A Student Activity**

**Objective:**
Hanhyun and Gwangwoo are experimenting with lenses to understand the focal lengths and indices of refraction in different mediums.

**Background:**
They have selected a double convex lens with the following specifications:
- Radius of curvature, R1 = 9.00 cm
- Radius of curvature, R2 = 11.0 cm
- Focal length in air, f_air = 5 cm

**Questions:**
1. What is the index of refraction of the lens in air?
2. What is its focal length in water, which has an index of refraction of 1.33?

**Formulae:**
1. Lens Maker's Equation:
   \[
   \frac{1}{f} = (n-1)\left(\frac{1}{R_1} - \frac{1}{R_2}\right)
   \]

2. Adjusting focal length when placed in a different medium:
   \[
   \frac{1}{f_{medium}} = \left(\frac{n_{lens}}{n_{medium}} - 1 \right)\left(\frac{1}{R_1} - \frac{1}{R_2}\right)
   \]

**Instructions:**
1. Substitute the given values into the Lens Maker's Equation to find the index of refraction in air.
2. Use the index of refraction found in part 1, along with the given index of refraction of water, to find the new focal length of the lens in water.

**Diagram:**
Unfortunately, no graphical representation is provided in the original text. However, a schematic representation of a double convex lens with radii R1 and R2 and focal points can be helpful for understanding.

Such calculations and practical activities will deepen understanding of light behavior through different media and enhance comprehension of core optical principles.
Transcribed Image Text:**Experimenting with Lenses: A Student Activity** **Objective:** Hanhyun and Gwangwoo are experimenting with lenses to understand the focal lengths and indices of refraction in different mediums. **Background:** They have selected a double convex lens with the following specifications: - Radius of curvature, R1 = 9.00 cm - Radius of curvature, R2 = 11.0 cm - Focal length in air, f_air = 5 cm **Questions:** 1. What is the index of refraction of the lens in air? 2. What is its focal length in water, which has an index of refraction of 1.33? **Formulae:** 1. Lens Maker's Equation: \[ \frac{1}{f} = (n-1)\left(\frac{1}{R_1} - \frac{1}{R_2}\right) \] 2. Adjusting focal length when placed in a different medium: \[ \frac{1}{f_{medium}} = \left(\frac{n_{lens}}{n_{medium}} - 1 \right)\left(\frac{1}{R_1} - \frac{1}{R_2}\right) \] **Instructions:** 1. Substitute the given values into the Lens Maker's Equation to find the index of refraction in air. 2. Use the index of refraction found in part 1, along with the given index of refraction of water, to find the new focal length of the lens in water. **Diagram:** Unfortunately, no graphical representation is provided in the original text. However, a schematic representation of a double convex lens with radii R1 and R2 and focal points can be helpful for understanding. Such calculations and practical activities will deepen understanding of light behavior through different media and enhance comprehension of core optical principles.
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