A simple camera telephoto lens consists of two lenses. The objective lens has a focal length f1 cm. The object to be photographed is 3.92 m in front of the objective lens. How far behind the concave lens should the film be placed? = +40.8 cm. Precisely 36.6 cm behind this lens is a concave lens with a focal length f2 = -14.8
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What is the lateral magnification of this lens combination?
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- Oliver has had a stamp collection since he was a boy. In those days, holding a stamp 10 cm from his eye gave him a clear image. Now, his near point has receded to 90 cm, so he holds a magnifying lens directly in front of his eye to let him bring stamps closer. To the nearest diopter, what power lens enables him to focus on a stamp 10 cm away?While you are photographing a dog, it begins to move away.What must you do to keep it in focus?(a) Increase the f-stop value.(b) Decrease the f-stop value.(c) Move the lens away from the sensor or film.(d) Move the lens closer to the sensor or film.(e) None of the above.Suppose, that two thin converging lenses of focal lengths 10 cm and 20 cm are separated by 20.0 cm, as illustrated in Figure. An object is placed 15.0 cm to the left of lens 1. Find the position of the final image and the magnification of the system.
- hiA 72 year old woman has a near point of 88 cm. What power lens (in diopters) does the woman need in order to be able to see an object clearly at the normal near point of 25 cm? Assume that the woman will get contact lenses, that is neglect the two centimeters that glasses would be away from the eye. 3805 This is an example of farsightedness. The correcting lens (converging in this case) has to move the (virtual) Image of an object placed at the normal near point (o) to the actual near point d the worhan (1). Then you can calculate the focal length of the lens. Remember that the image is virtual. Sub A Incorrect. Tries 1/99 Previous Tries Post Discussion Send FeedbWhat is the magnification of an object 15.0 cm from a 20.0 cm focal length thin spherical lens? O 0.6 inverted O 2 inverted 4 upright O 1.3 upright O 0.75 upright
- A small object is placed to the left of a convex lens and on its optical axis. The object is 46 cm from the lens, which has a focal length of 15 cm. Determine the location of the image formed by the lens. (Enter your answer in cm from the lens.) cm Describe the image. (Select all that apply.) realvirtualuprightinvertedenlargedreducedon the left side of the lenson the right side of the lenshas a magnifying A compound power of 100 when the image is formed at infinity. The objective has a focal length of 0.5 cm and the tube length is 6.5 cm. Find the focal length of the eye piece.Assume that the near point of a hyperopic (farsighted) eye is 0.936 m in front of the eye. A lens is used to let the eye see clearly an object that is 0.250 m in front of the eye. Ignore the small distance from the lens to the eye. What is the power of the lens (in diopters; answer sign and magnitude)?
- An object with a height of -0.040 m points below the principal axis (it is inverted) and is 0.200 m in front of a diverging lens. The focal length of the lens is -0.27 m. (Include the sign of the value in your answers.) (a) What is the magnification? (b) What is the image height? m (c) What is the image distance? mAn astronomical telescope has an angular magnification of -409 when used properly. What would the angular magnification M be if the objective and the eyepiece were interchanged?Which of the following statements is true about an eye that is farsighted? Question 17 options: The image is in front of the retina, and this can be corrected by a converging lens. The image is in back of the retina, and this can be corrected by a converging lens.