= An object of height 2.5 cm is placed at 28 cm in front of a diverging lens of focal length, f - 20 cm. Behind the diverging lens, there is a converging lens of focal length, f = 20 cm. The distance between the lenses is 3 cm. In the next few steps, you will find the location and size of the final image. Hint a. Where is the intermediate image formed by the first diverging lens? Image distance from first lens is di1 = cm. (Use the sign to indicate which side the image is on; positive sign means image is on the side of outgoing rays, and negative sign means image is on the side opposite to the outgoing rays.) b. Where is the final image formed by the second converging lens? Image distance from second lens is d₂2 = cm. (Use the sign to indicate which side the image is on.) c. How large is the intermediate image formed by the first diverging lens? Intermediate image height is hil = cm. (Use the sign to indicate whether the image is upright (positive) or inverted (negative).)
= An object of height 2.5 cm is placed at 28 cm in front of a diverging lens of focal length, f - 20 cm. Behind the diverging lens, there is a converging lens of focal length, f = 20 cm. The distance between the lenses is 3 cm. In the next few steps, you will find the location and size of the final image. Hint a. Where is the intermediate image formed by the first diverging lens? Image distance from first lens is di1 = cm. (Use the sign to indicate which side the image is on; positive sign means image is on the side of outgoing rays, and negative sign means image is on the side opposite to the outgoing rays.) b. Where is the final image formed by the second converging lens? Image distance from second lens is d₂2 = cm. (Use the sign to indicate which side the image is on.) c. How large is the intermediate image formed by the first diverging lens? Intermediate image height is hil = cm. (Use the sign to indicate whether the image is upright (positive) or inverted (negative).)
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Transcribed Image Text:### Exploring the Formation of Images Through Lenses
An object of height 2.5 cm is placed at 28 cm in front of a diverging lens of focal length \( f = -20 \) cm. Behind the diverging lens, there is a converging lens of focal length \( f = 20 \) cm. The distance between the lenses is 3 cm. In the next few steps, you will find the location and size of the final image.
**Hint**
#### Steps to Solve:
**a.** **Determine the Intermediate Image Formed by the First Diverging Lens**
- **Question:** Where is the intermediate image formed by the first diverging lens?
- **Variable:** Image distance from the first lens is \( d_{i1} = \) cm.
- **Instruction:** Use the sign to indicate which side the image is on; positive sign means the image is on the side of outgoing rays, and the negative sign means the image is on the side opposite to the outgoing rays.
**b.** **Determine the Final Image Formed by the Second Converging Lens**
- **Question:** Where is the final image formed by the second converging lens?
- **Variable:** Image distance from the second lens is \( d_{i2} = \) cm.
- **Instruction:** Use the sign to indicate which side the image is on.
**c.** **Determine the Size of the Intermediate Image Formed by the First Diverging Lens**
- **Question:** How large is the intermediate image formed by the first diverging lens?
- **Variable:** Intermediate image height is \( h_{i1} = \) cm.
- **Instruction:** Use the sign to indicate whether the image is upright (positive) or inverted (negative).
**d.** **Determine the Size of the Final Image Formed by the Second Converging Lens**
- **Question:** How large is the final image formed by the second converging lens?
- **Variable:** Final image height is \( h_{i2} = \) cm.
- **Instruction:** Use the sign to indicate whether the image is upright or inverted.
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By following these steps, you will be able to analyze the optical system involving a diverging and converging lens setup and understand the formation and characteristics of images produced by different types of lenses.
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